Question

有没有办法将这个查询翻译成Laravel雄辩的格式？

SELECT TEMP.A, COUNT(*) AS Total FROM 
      (SELECT A FROM TABLE WHERE B='something' GROUP BY C) 
AS TEMP GROUP BY TEMP.A

我在这里要做的是根据特定where子句中C的不同记录得到A的计数。

subselect语句也是由用户输入在过滤器上构建的雄辩对象，用于获取C out的不同记录。我尝试这样做，假设subselect eloquent对象是$ query

$query2->DB::connection()->table(function($_query) use ($query){
  $_query = $query;
  $_query->addSelect('A')->where('B','=','something')->groupBy('C')->get();
})->addSelect('A')->addSelect(DB::raw('COUNT(*) as Total'))->groupBy('A')->get();

但它似乎没有起作用，有人建议使用DB :: raw in - ＆gt; table（），但问题是subselect语句实际上也是一个动态构建的eloquent语句。

非常感谢您提前提供的帮助

Answer 1

子查询与Eloquent不能很好地协作。你只是给自己头疼，敢于尝试。我建议使用DB：select（），然后在模型中添加hydrate（），并使用它将其转换为Eloquent。这就是我处理复杂查询的方式：

包含查询的文件：

<?php
    $query = "SELECT TEMP.A, COUNT(*) AS Total FROM (SELECT A FROM TABLE WHERE B='?' GROUP BY C) AS TEMP GROUP BY TEMP.A";
    $thing_query = DB::select($query, ['something']);
    $thing = Thing::hydrate($thing_query);
    // hydrate converted it into Eloquent so we can use things like first()
    return $thing->first()->total;

模型/ Thing.php

<?php
class Thing extends Eloquent {
    /**
     * Hydrate method
     * 
     * @param array $data
     * @return Illuminate\Database\Eloquent\Collection
     */
    static public function hydrate(array $data, $connection = NULL)
    {
        // get calling class so we can hydrate using that type
        $klass = get_called_class();

        // psuedo hydrate
        $collection = new Illuminate\Database\Eloquent\Collection();
        foreach ($data as $raw_obj)
        {
            $model = new $klass;
            $model = $model->newFromBuilder($raw_obj);
            if (!is_null($connection))
                $model = $model->setConnection($connection);
            $collection->add($model);
        }
        return $collection;

    }
}

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