我正在尝试将文本绘制到位于2d数组正方形中的一堆rects上方的空间中的屏幕上。当我尝试在屏幕上绘制文本时，它会说“在blit期间不得锁定曲面。”
我尝试过解锁，没有任何区别。
import sys, time, random, pygame
from pygame import *
from time import time,sleep
pygame.init()
global isDragging, inDrag, rightDrag, lastDrag, inDragRight, mouseX,mouseY, borderHeight
isDragging = False
isAuto = False
inDrag= False
inDragRight = False
isFilling = False
done = False
lastDrag = None
rightDrag = None
tickTime = 300
font = pygame.font.SysFont(None, 12,False,False)
dragDelay = 2
BLACK = ( 0, 0, 0)
WHITE = ( 255, 255, 255)
GREEN = ( 0, 255, 0)
RED = ( 255, 0, 0)
PINK = ( 255, 150, 200)
BLUE = ( 0, 0, 255)
RED = GREEN
width, height, margin = 100, 100, 1
noWidth, noHeight = 6,6
speed = [2, 2]
borderHeight = 50
size = (width*noWidth,height*noHeight + borderHeight)
screen = pygame.display.set_mode(size)
pygame.display.set_caption("PieStone")
clock = pygame.time.Clock()
pixArray = pygame.PixelArray(screen)
font = pygame.font.SysFont("monospace", 15)
word = font.render("test", 1, (0, 0, 0))
class Null:
pass
square = [[Null() for i in range(noHeight)]for i in range(noWidth)]
for d1 in range(noWidth):
for d2 in range(noHeight):
square[d1][d2].man = False
square[d1][d2].visits = 0
square[d1][d2].colour = BLACK
square[d1][d2].margin = 1
a = 1
i = 1
def text(word,size,pos1,pos2,pos3):
word = font.render(str(word),size,(pos1,pos2,pos3))
return word
def colide(obj,mouseX,mouseY):
if obj.collidepoint(mouseX,mouseY) == 1:
return True
else:
return False
def click(mouseX,mouseY):
#rint("left")
global inDrag,lastDrag
for d1 in range(noWidth):
for d2 in range(noHeight):
if colide(square[d1][d2].rect,mouseX,mouseY):
square[d1][d2].man = True
#print("square",d1,d2,"has been clicked")
try:
if square[d1][d2] != lastDrag:
inDrag = True
lastDrag = square[d1][d2]
else:
inDrag = False
except UnboundLocalError:
print("error")
lastDrag = square[d1][d2]
#print(inDrag)
if square[d1][d2].margin == 0 and inDrag:
square[d1][d2].margin = 1
square[d1][d2].visits = square[d1][d2].visits + 1
elif square[d1][d2].margin == 1 and inDrag:
square[d1][d2].margin = 0
square[d1][d2].visits = square[d1][d2].visits + 1
break
'''if square[d1][d2].visits >= 5 and square[d1][d2].colour == BLACK:
square[d1][d2].visits = 0
square[d1][d2].colour = RED
elif square[d1][d2].visits >= 5 and square[d1][d2].colour == RED:
square[d1][d2].visits = 0
square[d1][d2].colour = BLACK'''
def rightClick(mouseX,mouseY):
#print("right")
global inDragRight, lastRight
for d1 in range(noWidth):
for d2 in range(noHeight):
if colide(square[d1][d2].rect,mouseX,mouseY):
square[d1][d2].man = True
#print("colide")
try:
if square[d1][d2] != lastRight:
inDragRight = True
lastRight = square[d1][d2]
else:
inDragRight = False
except:
print("error")
lastRight = square[d1][d2]
#print(inDragRight)
if square[d1][d2].colour == RED and inDragRight:
square[d1][d2].colour = BLACK
#print("black")
elif square[d1][d2].colour == BLACK and inDragRight:
square[d1][d2].colour = RED
#print("red")
break
while not done:
screen.blit(word, (0, 0))
(mouseX,mouseY) = pygame.mouse.get_pos()
#print(str(mouseX)+",",mouseY)
for event in pygame.event.get(): # User did something
if event.type == pygame.QUIT: # If user clicked close
done = True # Flag that we are done so we exit this loop
elif event.type == pygame.MOUSEBUTTONDOWN:
#print(mouseX,mouseY)
if pygame.mouse.get_pressed()[0] == 1:
isDragging = True
if pygame.mouse.get_pressed()[2] == 1:
isFilling = True
elif pygame.mouse.get_pressed()[1] == 1:
isAuto = True
#print(pygame.mouse.get_pressed())
elif event.type == pygame.MOUSEBUTTONUP:
#print("up")
isDragging = False
isFilling = False
lastDrag = None
lastRight = False
if pygame.mouse.get_pressed()[0] == 1:
isDragging = True
if pygame.mouse.get_pressed()[2] == 1:
isFilling = True
if isAuto:
rnd1 = random.randint(0,1)
if rnd1 == 1:
isDragging = True
isFilling = False
else:
isDragging = False
isFilling = True
(mouseX,mouseY) = (random.randint(0,width*noWidth),random.randint(0,height*noHeight)+borderHeight)
#print(mouseX,mouseY)
if isDragging:
click(mouseX,mouseY)
if isFilling:
rightClick(mouseX,mouseY)
screen.fill(WHITE)
# --- Game logic should go here
i = 0
for d1 in range(noWidth):
if noHeight % 2 == 0:
'''if i == 0:
i = 1
else:
i = 0'''
for d2 in range(noHeight):
#if i % a == 0:
try:
if i == 0:
pass
elif i == 1:
pass
except AttributeError:
print("AttributeError")
square[d1][d2].margin = random.randint(0,1)
#print(square[d1][d2].visits)
square[d1][d2].rect = pygame.draw.rect(screen, square[d1][d2].colour, [(d1*width), ((d2*height)+borderHeight),width,(height)],square[d1][d2].margin)
#print("d1*width:",d1*width,"d2*height:",d2*height,"d1*width+width:",d1*width+width,"d2*height+height:",d2*height+height)
pygame.display.flip()
clock.tick(tickTime)
# Close the window and quit.
# If you forget this line, the program will 'hang'
# on exit if running from IDLE.
pygame.quit()
答案 0 :(得分：2)
您正在使用PixelArray：
pixArray = pygame.PixelArray(screen)
但使用PixelArray会锁定您的Surface，如文档中所述：
在PixelArray的生命周期中，PixelArray会锁定曲面，因此一旦不再使用它就明确地必须删除它，并且曲面应该在相同的范围内执行操作。
只需删除该行，因为您还没有使用它。