我的数据如下:
[
{
"_id": "531dbf8b9b9fc50000a8d611",
"active": true,
"client": {
"_id": "531dbf8b9b9fc50000a8d60e",
"name": "TR"
},
"company_id": "531dbf8b9b9fc50000a8d60c",
"createdOn": "2014-03-10T13:35:07.313Z",
"description": "Gentle Action Application Pads",
"dimensions": {
"weight": 22.4
},
"lot": [
],
"meta": {
"category": "Face",
"msrp": 7.75
},
"sku": "11002",
"unit_of_measure": "each",
"updatedOn": "2014-03-10T13:35:07.314Z"
},
{
"_id": "531dbf8b9b9fc50000a8d612",
"active": true,
"client": {
"_id": "531dbf8b9b9fc50000a8d60e",
"name": "TR"
},
"company_id": "531dbf8b9b9fc50000a8d60c",
"createdOn": "2014-03-10T13:35:07.317Z",
"description": "Skin Renewal System - Enriched (CA)",
"dimensions": {
"weight": 22.4
},
"lot": [
],
"meta": {
"category": "Face",
"msrp": 321.6
},
"sku": "11700CA",
"unit_of_measure": "each",
"updatedOn": "2014-03-10T13:35:07.318Z"
}
]
在我看来,我有:
<input type="text" ng-model="receivingSku" placeholder="Locations loaded via $http" typeahead="sku for sku in getSku($viewValue) | filter:$viewValue" typeahead-on-select="selectedSku()" class="form-control">
我需要每个项目的sku
字段在typeahead中。我怎么能做到这一点?
目前,我收到一个错误:
Error: matches is undefined
答案 0 :(得分:1)
您可以遍历原始数组并创建一个仅包含SKU的数组:
var skus = origArray.map(function(e) {
return e.sku;
});
新数组可用于预先输入。
PS - 我对typeahead不太熟悉。如果typeahead能够窥视对象,则不需要这样做。