Question

我正在使用Flask应用程序，其中我有一个LargeGroupAttendance模型，该模型引用另一个名为Attendee的模型。我正在尝试请求所有符合特定条件的LargeGroupAttendance对象，但我试图通过参加者模型的列对它们进行排序 - 这是否可能？以下是两种型号：

""" Attendeee Class """
class Attendee(Base):
    __tablename__ = 'attendee'

    id = Column(Integer, primary_key=True)
    first_name = Column(String(200))
    last_name = Column(String(200))
    year = Column(String(200))
    email = Column(String(100), unique=True)
    dorm = Column(String(100))

    def __init__(self, first_name, last_name, year, email, dorm):
        self.first_name = first_name
        self.last_name = last_name
        self.year = year
        self.email = email
        self.dorm = dorm

    def __repr__(self):
        return '<Attendee %r>' % self.first_name

""" Large Group Attendance Class """
class LargeGroupAttendance(Base):
    __tablename__ = 'large_group_attendance'

    id = Column(Integer, primary_key=True)
    first_time = Column(Integer)

    large_group_id = Column(Integer, ForeignKey('large_group.id'))
    large_group = relationship("LargeGroup", backref=backref('large_group_attendance', order_by=id))

    attendee_id = Column(Integer, ForeignKey('attendee.id'))
    attendee = relationship("Attendee", backref=backref('large_group_attendance', order_by=id))

我是否需要在我的与会者课程中添加一些内容才能实现这一目标？这是我之前尝试过的一个查询，但它没有输出（也没有错误......）。我哪里错了？

    attendance_records = db.session.query(LargeGroupAttendance).filter_by(large_group_id=event_id).order_by(desc(LargeGroupAttendance.attendee.first_name))

Answer 1

我认为您需要在查询中添加联接，如下所示：

.join(LargeGroupAttendance.attendee)

以便最终查询如下所示：

attendance_records = (db.session.query(LargeGroupAttendance).
    filter_by(large_group_id = event_id).
    join(Attendee, LargeGroupAttendance.attendee).
    order_by(desc(Attendee.first_name))
    )

有关更详细的说明，请参阅SQLAlchemy: How to order query results (order_by) on a relationship's field?

Flask SQLAlchemy order_by关系

1 个答案: