Python正则表达式删除所有出现的[Number]

Question

我正在寻找python中的正则表达式语句，它将从字符串中删除[1]或[17]或基本上[*]的所有出现。出现如下*其中*等于某个数字：

[*]
[ * ]
[ *]
[* ]

目前我有：

re.sub(r'\[*\]', '', origional_string)

提出invalid expression

示例输入字符串：

makeup of organisms.[10] In 1997, while working at the University of Tennessee, Pigliucci received the Theodosius Dobzhansky Prize,[11] 

预期产出：

makeup of organisms. In 1997, while working at the University of Tennessee, Pigliucci received the Theodosius Dobzhansky Prize,

Answer 1

我想这样的事情应该有效：

import re

origional_string = "makeup of organisms.[10] In 1997, while working at the University of Tennessee, Pigliucci received the Theodosius Dobzhansky Prize,[11]"

result = re.sub(r'\[ *[0-9]+ *\]', '', origional_string)

print(result)

[0-9]+匹配一个或多个数字，而 *匹配空格（如果有）。

ideone demo

Answer 2

\d表示正则表达式中的数字。我还在这里的数字周围添加了选项\s。

re.sub(r'\[\s*\d+\s*\]', '', origional_string)

Answer 3

 >>> import re
 >>> re.sub(r'\[\s*\d+\s*\]', '', original_string)