Question

我有一个Rails控制器，我正在尝试返回一个json对象，该对象由从遗留SQL Server数据库派生的几个关联模型组成。由于我是新手并且正在尝试，我只在一个相关模型上使用“：include”，直到我可以使其工作，然后提高赌注。

控制器：

class SlotMachineEntityController < ApplicationController
  def retrieveAll
      @blah = Machine.where("Machine.CasinoID = 2").find(1, :select => "Machine.MachineID", :include => :slot_instance)

      respond_to do |format|
          format.json { render :json => @blah }
      end
  end
end

错误是：

TinyTds ::错误：列名“ machine_id ”无效：...... [Master]。[SlotInstance]。[Active] AS t1_r10 FROM [Master]。[Machine] LEFT OUTER JOIN [Master]。[SlotInstance] ON [Master]。[SlotInstance]。[ machine_id ] = [Master]。[Machine]。[MachineID] WHERE [Master]。[Machine]。[MachineID] = @ 0 AND（Machine.CasinoID = 2）'， N'@ 0 int'，@ 0 = 1

推测错误发生在它尝试执行“：include =＆gt;：slot_instance”并通过查找“machine_id”而不是“MachineID”（这是数据库中使用的密钥）而恢复为默认命名约定。我找不到我指定的语法：include方法，外键是MachineID而不是machine_id。

供参考，相关型号为：

class Machine < ActiveRecord::Base
    self.table_name = "Master.Machine"
    set_primary_key "MachineID"

    has_one :slot_instance
    belongs_to :manufacturer, :foreign_key => "ManufacturerID"
    belongs_to :casino, :foreign_key => "CasinoID"
    belongs_to :customer, :foreign_key => "CustomerID"
end

class SlotInstance < ActiveRecord::Base
    self.table_name = "Master.SlotInstance"
    set_primary_key "SlotInstanceID"

    belongs_to :game_configuration, :foreign_key => "GameConfigurationID"
    belongs_to :customer, :foreign_key => "CustomerID"
    belongs_to :casino, :foreign_key => "CasinoID"
    belongs_to :location, :foreign_key => "LocationID"
    belongs_to :machine, :foreign_key => "MachineID"
end

感谢您的帮助！

Answer 1

您需要在机器类的has_one关系中指定外键，即

has_one :slot_instance, :foreign_key => "MachineID"

Rails - 如何在使用时显式指定外键：在控制器中包含方法

1 个答案: