如何在php中获取没有文件名的文件路径？

Question

例如，这是$ _SERVER ['HTTP_HOST']。 $ _SERVER ['REQUEST_URI']输出：

example.com/foldername/subfolder/controller/index.php

我想以example.com/foldername/subfolder/controller /

结束

谢谢..

Answer 1

查看http://php.net/manual/en/function.pathinfo.php

<?php
$path_parts = pathinfo('/www/htdocs/inc/lib.inc.php');

echo $path_parts['dirname'], "\n";
echo $path_parts['basename'], "\n";
echo $path_parts['extension'], "\n";
echo $path_parts['filename'], "\n"; // since PHP 5.2.0
?>

该输出将是

/www/htdocs/inc
lib.inc.php
php
lib.inc

因此，简而言之，您可以使用$path_parts['dirname']。

Answer 2

print_r( $_SERVER );

http://www.php.net/manual/en/reserved.variables.server.php http://www.php.net/manual/en/language.constants.predefined.php

PATH_TRANSLATED or __DIR__

很多选项=）

Answer 3

将两者合在一起以获得

$url = "http://". $_SERVER['HTTP_HOST'] . $_SERVER['REQUEST_URI'];