Question

我得到了

bus_stops0.txt    
01012,Victoria St,Hotel Grand Pacific
01013,Victoria St,St. Joseph's Ch
01019,Victoria St,Bras Basah Cplx

在记事本中，我不知道如何在IDLE中打开这个文件。

另外，我想定义

def read_data(filename):
    stops = [] 
    with open(filename,  'r') as f:
        for line in f:
            line = line[:-1]
            code, road_name, desc = line.split(',')
            stops.append(filename)
    return str(stops)

这样

read_data('bus_stops0.txt')

['01012，Victoria St，Hotel Grand Pacific'，“01013，Victoria St，St.Joseph's Ch”，'01019，Victoria St，Bras Basah Cplx']

首先我的定义是否正确？

Answer 1

对于所需的输出，定义为：

def read_data(filename):
   stops = []
   with open(filename,  'r') as f:
       for line in f:
           stops.append(line.replace('\n', ''))
   return str(stops)

Answer 2

将U标志用于通用读取模式。

def read_data(filename):
   stops = []
   with open(filename,  'rU') as f:
       for line in f:
           stops.append(line.strip())
   return stops

或者，如果您想保留换行符，只需返回readlines

即可

def read_data(filename):
   with open(filename,  'rU') as f:
       return f.readlines()

Answer 3

如果'stops'是每个文件行的第三个元素，并且您想使用列表推导：

def read_data(filename):
    with open(filename,  'r') as f:
        stops = [line.split(',')[-1] for line in f]
return str(stops)

Answer 4

如果我理解正确，你需要像这样的输出

['01012,Victoria St,Hotel Grand Pacific', "01013,Victoria St,St. Joseph's Ch", '01019,Victoria St,Bras Basah Cplx']

如果是这种情况，那么这里是代码。确保文件具有读取权限。

def read_data(filename):
    stops = []
    with open(filename,  'r') as fobj:
       for line in fobj:
           stops.append(line.strip())
    return stops

在Python中读取文件以获取文本

4 个答案: