<html>
<apex:includeScript value="//cdn.jsdelivr.net/jquery/1.7/jquery.min.js"/>
<table width="100%">
<tr>
<td width="84%">
<apex:form id="form1" >
<table bgcolor="#00C4FF" style="position:fixed;" width="100%" height="80">
<tr>
<td >
<b style="color:white;"> From :</b>
</td>
<td>
<apex:selectList value="{!operator}" size="1" id="operator" styleClass="input">
<apex:selectOption itemValue="=" itemLabel="Equal" />
<apex:selectOption itemValue="!=" itemLabel="Not Equal To"/>
<apex:selectOption itemValue="<=" itemLabel="Less Or Equal"/>
<apex:selectOption itemValue=">=" itemLabel="Greater Or Equal"/>
<apex:selectOption itemValue=">" itemLabel="Greater Than"/>
<apex:selectOption itemValue="<" itemLabel="Less Than"/>
<apex:selectOption itemValue="Like" itemLabel="Like"/>
</apex:selectList>
</td>
<td> <apex:inputText value="{!inputText1}" id="autocomplete1" styleClass="input"/>
</td>
<td>
<apex:commandButton value="Default View" action="{!showlist}" styleClass="input"/>
</td><td></td></tr></table><br/><br/><br/>
</apex:form></td><td style="padding-top:173px;">
<button id="plusBtn" width="20px">+</button>
<button id="minusBtn" width="20px">-</button></td></tr></table>
</html>
//当表格内的按钮不能正常工作时。当表格外的按钮正在调用javascript时,它不会调用javascript。工作正常
<button id="plusBtn" width="20px">+</button>
<button id="minusBtn" width="20px">-</button>
Java script:
<script type="text/javascript">
$(document).ready(function(){
var currFFZoom = 1;
var currIEZoom = 100;
var button1 = document.getElementById("plusBtn");
$(button1).on('click',function(){
if ($.browser.mozilla){
var step = 0.02;
currFFZoom += step;
$("[id$=tblQuotes]").css('-moz-transform', 'scale(' + currFFZoom + ')');
} else {
var step = 2;
currIEZoom += step;
$("[id$=tblQuotes]").css('zoom', currIEZoom + '%');
}
});
$('#minusBtn').on('click',function(){
if ($.browser.mozilla){
var step = 0.02;
currFFZoom -= step;
$("[id$=tblQuotes]").css('-moz-transform', 'scale(' + currFFZoom + ')');
} else {
var step = 2;
currIEZoom -= step;
$("[id$=tblQuotes]").css('zoom', currIEZoom + '%');
}
});
});
</script>
当表中的按钮不能正常工作时。当表调用javascript时,表中的按钮不会调用javascript。它工作正常
答案 0 :(得分:0)
最好的我可以不看HTML:
更改
var button1 = document.getElementById("plusBtn");
$(button1).on('click',function(){
要
var button1 = $("#plusBtn");
button1.click(function(){