Question

我正在尝试以格式

开发json feed

{
    "contacts": [
        {
                "id": "c200",
                "name": "Ravi Tamada",
                "email": "ravi@gmail.com",
                "address": "xx-xx-xxxx,x - street, x - country",
                "gender" : "male",
                "phone": {
                    "mobile": "+91 0000000000",
                    "home": "00 000000",
                    "office": "00 000000"
                }
        },
        {
                "id": "c201",
                "name": "Johnny Depp",
                "email": "johnny_depp@gmail.com",
                "address": "xx-xx-xxxx,x - street, x - country",
                "gender" : "male",
                "phone": {
                    "mobile": "+91 0000000000",
                    "home": "00 000000",
                    "office": "00 000000"
                }
        },


  ]
}

使用以下代码

public class Phone
{
    public string mobile { get; set; }
    public string home { get; set; }
    public string office { get; set; }
}

public class Cont
{
    public string sno { get; set; }
    public string name { get; set; }
    public string em { get; set; }
    public string address { get; set; }
    public string gender { get; set; }
    public Phone phone { get; set; }
}

public class RootObject
{
    public List<Cont> contacts { get; set; }
}

和

var objectToSerialize = new RootObject();
      //  var aa = new Cont();
        objectToSerialize.contacts = new List<Cont> 
                          {
                             new Cont { sno = "test1", name = "index1" , address = "index1",gender="male",em="scd", phone={mobile="ff",home="ff",office="ff"}}
                           //  new Item { name = "test2", index = "index2" }
                          };

        JavaScriptSerializer serializer = new JavaScriptSerializer();
        Response.Write(serializer.Serialize(objectToSerialize));

使用此代码无法获取我的输出，我也将对象引用未设置为实例..

我添加了我的所有代码。

任何一个人帮助我的代码出错了

Answer 1

这是你的对象初始化程序中的问题：

phone={mobile="ff",home="ff",office="ff"}

这是尝试设置现有 Phone对象的属性。换句话说，它正在执行：

var tmp = new Cont();
tmp.sno = "test1";
...
tmp.phone.mobile = "ff";
tmp.phone.home = "ff";
...

...没有将tmp.phone的值设置为非空引用。

你要么：

phone=new Phone {mobile="ff",home="ff",office="ff"}

或者您需要更改Cont类，以便为其初始化Phone提供构造函数：

public Cont()
{
    phone = new Phone();
}

我还强烈建议您遵循属性的.NET命名约定，并为您的班级提供Contact而不是Cont的全名。避免毫无意义地缩写。

您应该能够将序列化程序配置为在JSON中使用小写名称，而不会使.NET名称变得丑陋。

Answer 2

尝试http://james.newtonking.com/json
尝试初始化手机属性

对象引用未设置为json中对象错误的实例

2 个答案: