Question

我试着编写一个关于找到两个序列的中位数的程序，这并不难，但我停止了购买输入两个序列部分。

以前从不考虑这个问题，总是尝试while(cin>> temp)，但不知道为什么这次失败。

当我编译它时，第一个循环输入是OK，但是当第二个循环开始时，编译器会发出＆＃34; vector iterator而不是dereferencable＆＃34;

#include <iostream>
#include <vector>

using namespace std;

template< class T>
T median(vector<T>& s1, vector<T>& s2) {
T m(0);

auto itr1 = s1.begin();
auto itr2 = s2.begin();
int counts = (s1.size() + s2.size() -1 ) / 2 ;

    for (int i = 0; i < counts; ++i){
        if ((*itr1 < * itr2) && ( itr1+1 != s1.end()))
            ++itr1;
        else
            ++itr2;
    }

    m = (*itr1 + *itr2) / 2;
    return m;
}

int main() {
    vector<int> s1; 
    vector<int> s2;
    cout << " Please input the number in the first sequence " << endl;
    int temp;

    while (cin >> temp) {
        s1.push_back(temp);
    }

    cout << " Please input the number in the second sequence " << endl;
    int temp2;

    while (cin >> temp2){
        s2.push_back(temp2);
    }

    cout << " The median of these two sequences is " << median<int>(s1, s2) << endl;

    return 0;
}

Answer 1

您可以使用非数字输入作为停止的符号。它会停在任何键上，不仅是'q'，而且你还可以添加额外的支票等等。

cout << " Please input first sequence numbers (press 'q' to finish)" << endl;

while (cin >> temp)
    s1.push_back(temp);

cin.clear();

// ignore all symbols before '\n'
cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');

cout << " Please input second sequence numbers (press 'q' to finish)" << endl;

while (cin >> temp)
   s2.push_back(temp);

关于输入数据

1 个答案: