为什么将此Python POST请求转换为Java不起作用?

时间:2014-03-09 19:54:03

标签: java android python http post

我正在尝试使用Python Requests HTTP库将此Python代码转换为Java代码(适用于Android)。

import requests
payload = {"attr[val1]":123,
           "attr[val2]":456,
           "time":0,
           "name":"Foo","surname":"Bar"}

r = requests.post("http://jakiro.herokuapp.com/api", data=payload)
r.status_code
r.text

这是我到目前为止所做的:

protected void sendJson() {
    Thread t = new Thread() {

        public void run() {
            Looper.prepare(); //For Preparing Message Pool for the child Thread
            HttpClient client = new DefaultHttpClient();
            HttpConnectionParams.setConnectionTimeout(client.getParams(), 10000); //Timeout Limit
            HttpResponse response;
            JSONObject json = new JSONObject();

            try {
                Log.v("SOMETHING_NAME3", "Creating POST");
                HttpPost post = new HttpPost("http://jakiro.herokuapp.com/api");
                json.put(MessageAttribute.SURNAME, "Bar");
                json.put(MessageAttribute.VAL1, 123);
                json.put(MessageAttribute.VAL2, 456);
                json.put(MessageAttribute.name, "Foo");
                json.put(MessageAttribute.TIME, 0);
                StringEntity se = new StringEntity( json.toString() );
                se.setContentType(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));
                post.setEntity(se);
                response = client.execute(post);

                /*Checking response */
                if(response!=null){
                    InputStream in = response.getEntity().getContent(); //Get the data in the entity
                    String foo = convertStreamToString(in);
                    Log.v("SOMETHING_NAME2", foo); // Gives me "Bad request"
                }

            } catch(Exception e) {
                e.printStackTrace();
                Log.v("SOMETHING_NAME", "Cannot Establish Connection");
            }

            Looper.loop(); //Loop in the message queue
        }
    };

    t.start();
}

我已经使用response.getStatusLine().getStatusCode()检查了响应,然后从服务器返回400。 Python代码可以正常工作,但是在Android设备上的Java中却没有。我无法弄清楚为什么会这样。

1 个答案:

答案 0 :(得分:0)

@ Blender的链接是链接上的正确解决方案:How to use parameters with HttpPost

url-encode的正确方法是创建BasicNameValuePairs并对其进行编码:

postParameters = new ArrayList<NameValuePair>();
postParameters.add(new BasicNameValuePair("param1", "param1_value"));
postParameters.add(new BasicNameValuePair("param2", "param2_value"));

httppost.setEntity(new UrlEncodedFormEntity(postParameters));