Question

我正试图从我的本地数据库中获取一个特定的值，但似乎它确实起作用，这是我的代码：

$acceptance = " SELECT acceptance_status FROM teams_0517 WHERE team_id=$team_id"; 
$acceptancex = mysql_query($acceptance);
mysql_close($connection);

if($acceptancex == 0)
{
    ob_clean();
    header('Location: index.php');
    ob_flush();
}
else
{
    ob_clean();
    header('Location: signup.php');
    ob_flush();
}

当我运行代码时，php将跳过if条件并继续执行其他语句，因此似乎$acceptance没有值..有什么帮助吗？

Answer 1

执行查询后需要获取结果。见how to fetch

尝试这样：

$acceptance = " SELECT acceptance_status FROM teams_0517 WHERE team_id=$team_id limit 1"; 
$result = mysql_query($acceptance);
$acceptancex = mysql_fetch_object($result); // fetch object


if($acceptancex->acceptance_status == 0)
{
    ob_clean();
    mysql_close($connection);
    header('Location: index.php');
    ob_flush();
}
else
{
    ob_clean();
    mysql_close($connection);
    header('Location: signup.php');
    ob_flush();
}

Answer 2

试试这个： -

$acceptance = " SELECT acceptance_status FROM teams_0517 WHERE team_id=$team_id limit 1"; 
$result = mysql_query($acceptance);
$acceptancex = mysql_fetch_object($result); // fetch object

if($acceptancex->acceptance_status == 0)
{
    $redirect = "index.php";
}
else
{
    $redirect = "signup.php";
}
mysql_close($connection);

ob_clean();
header('Location: '.$redirect);
ob_flush();

从数据库中获取值不起作用

2 个答案: