Question

经过几天的研究，我仍然对创建一个涉及4个表格的表格感到困惑，这些表格都是通过ForiegnKey连接的。我甚至不确定我是否使用了正确的方法。

我应该使用forms.Form还是ModelForm？我正在寻找的我确信很常见，但我的所有尝试都是徒劳的。由于所有4个表都是相关的，所以我觉得这比它应该更复杂。

要点：要创建工作订单，请选择一个建筑物，然后在该建筑物内挑选一个单元，然后从该单元内的租户中选择一个调用者。然后在视图中收集所有数据并保存WorkOrder。

使用Django 1.6

# models.py
class Building(models.Model):
    name = models.CharField(max_length=30)
    address = models.CharField(max_length=200)
    ...

def __unicode__(self):
    return self.name


class Unit(models.Model):
    name = models.ForeignKey(Building)
    unit = models.CharField(max_length=30)
    ...

    def __unicode__(self):
        return self.unit

class Tenant(models.Model):
    unit = models.ForeignKey(Unit)
    name = models.ForeignKey(Building)
    first_name = models.CharField(max_length=30)
    last_name = models.CharField(max_length=30)
    ...

    def __unicode__(self):
        return u'%s %s' % (self.first_name, self.last_name)


class WorkOrder(models.Model):
    name = models.ForeignKey(Building)
    unit = models.ForeignKey(Unit)
    ordernum = models.AutoField(primary_key=True)
    ...

    def __unicode__(self):
        return self.unit

forms.py

# forms.py

class WorkOrderForm(forms.Form):
    building_choice = forms.ModelChoiceField(queryset=Building.objects.all(),
                                             empty_label='Pick a building',
                                             )

    def __init__(self, *args, **kwargs):
        super(WorkOrderForm, self).__init__(*args, **kwargs)
        self.fields['building_choice'].label = 'Building'


    unit_choice = forms.ModelChoiceField(queryset=Unit.objects.(????),
                                         empty_label='Pick a unit',
                                         )

    def __init__(self, *args, **kwargs):
        super(WorkOrderForm, self).__init__(*args, **kwargs)
        self.fields['unit_choice'].label = 'Unit'

    caller_choice = forms.ModelChoiceField(queryset=Tenant.objects.(????),
                                       empty_label='Who called',
                                       )

    def __init__(self, *args, **kwargs):
        super(WorkOrderForm, self).__init__(*args, **kwargs)
        self.fields['caller_choice'].label = 'Tenant'

views.py（不完整）

#views.py
def create(request):
    if request.method == 'POST':
        form = WorkOrderForm(request.POST)
        if form.is_valid():
            workorder = WorkOrder(name=form.cleaned_data['name'],
                                 unit=form.cleaned_data['unit'],
                                 call_date=form.cleaned_data['call_date'],
                                 caller=form.cleaned_data['caller'],
                                 problem_desc=form.cleaned_data['problem_desc'])
            workorder.save()

            return HttpResponseRedirect('/workorder/')
    else:
        form = WorkOrderForm()
    return render(request, 'workorder_form.html', {'form': form})

如果有人能让我知道正确的方法，我将永远感激不尽。

Answer 1

自从我发布这个问题以来已经有一段时间了，但我找到了满足我需求的django包django-clever-selects。文档和示例项目得到了很好的评论。感谢早先帮助过的所有人。

django与ModelChoiceField一起形成

1 个答案: