Question

以下是包含表es_preadmission

的示例数据的模式

  admno  |pre_gender|pre_class| pre_scat_id |bpl |sgc |handi|ser_cat
---------|----------|---------|-------------|----|----|-----|--------
    1    |Male      |1        |GEN          |no  |no  |no   |1
    2    |Male      |1        |GEN          |no  |no  |no   |1
    3    |Male      |1        |GEN          |bpl |no  |no   |1
    4    |Female    |2        |GEN          |no  |sgc |no   |1
    5    |Male      |1        |SC           |no  |no  |no   |1
    6    |Female    |1        |GEN          |no  |no  |no   |1
    7    |Female    |2        |GEN          |no  |no  |no   |5
    8    |Male      |2        |GEN          |bpl |no  |no   |1
    9    |Male      |2        |ST           |no  |no  |no   |1
    10   |Male      |1        |OBC          |no  |no  |no   |3
    11   |Female    |1        |ST           |no  |no  |no   |5
    12   |Male      |2        |GEN          |no  |no  |no   |1
    13   |Male      |2        |SC           |no  |no  |PH   |1
    14   |Female    |2        |SC           |bpl |no  |no   |1
    15   |Female    |1        |GEN          |no  |no  |no   |2

**我正在尝试从每个类别（GEN，SC，ST，OBC），bpl，sgc，handi，ser_cat类明智地获得男女学生的数量。实施例

        1       2 
      M   F   M   F
GEN   20  9   25  10
SC    5   2   9   4
ST    0   3   0   0
OBC   1   2   1   0
PH    0   0   1   0
BPL   2   3   7   2

** 现在我要尝试上面这些数字 -

SELECT pre_scat_id AS cat, pre_gender, COUNT(admno)
FROM es_preadmission
WHERE pre_scat_id IN ('GEN','SC','ST','OBC')
GROUP BY pre_scat_id, pre_gender
UNION ALL
SELECT pre_handi AS cat, pre_gender, COUNT(admno)
FROM es_preadmission
WHERE pre_handi = 'Yes' OR pre_handi = 'No'
GROUP BY pre_handi, pre_gender
UNION ALL
SELECT pre_bpl AS cat, pre_gender, COUNT(admno)
FROM es_preadmission
WHERE pre_bpl = 'Yes' OR pre_bpl ='No'
GROUP BY pre_bpl, pre_gender;

但我没有得到理想的输出。以下输出基于上述查询在实际数据库上绘制。

cat|pre_gender|COUNT(admno)
GEN| Female   |216
GEN| Male     |371
OBC| Female   |30
OBC| Male     |50
SC | Female   |36
SC | Male     |65
ST | Male     |9
No | Female   |281
No | Male     |495
PH | Male     |1
No | Female   |268
No | Male     |467
bpl| Female   |13
bpl| Male     |25

需要帮助如何明智地获得输出类

Answer 1

您需要汇总不同的CASE，例如对于第一个SELECT：

SELECT pre_scat_id AS cat
  , COUNT(CASE WHEN pre_gender = 'Male'   AND pre_class = 1 THEN 1 END) AS M1
  , COUNT(CASE WHEN pre_gender = 'Female' AND pre_class = 1 THEN 1 END) AS F1
  , COUNT(CASE WHEN pre_gender = 'Male'   AND pre_class = 2 THEN 1 END) AS M2
  , COUNT(CASE WHEN pre_gender = 'Female' AND pre_class = 2 THEN 1 END) AS F2
FROM es_preadmission
WHERE pre_scat_id IN ('GEN','SC','ST','OBC')
GROUP BY pre_scat_id

使用MySQL计算多个条件下的操作

1 个答案: