Question

拼命编写一个脚本来读取文件中的每一行文本

确定该行是否包含单引号，从行

中删除该引号

如果超过2个没有动作

使用已编辑的行和未编辑的行创建新文件

我原本希望用我解析的方式遇到麻烦，但我实际上遇到意外的文件错误？

有人可以指导我退出或结束阅读吗？我搜索了大量的EOF主题，但它确实没有意义。

read -p "User file: " fileName
if [ ! -e $fileName ];
then
  echo ${fileName} doesn''t exist or is not a file
  exit 1
fi

# Check  |to see if it exists and throw and error if it doesn't
ls $fileName > /dev/null


cat $fileName 

while read line
count= 'grep " | wc -m' 
if [ "$count" < 2 ];
then
  $line | tr -d '"'

fi

echo  $filename >> newFile.csv

exit

Answer 1

read -p "User file: " fileName
if [ ! -e $fileName ];
then
  echo ${fileName} doesn''t exist or is not a file
  exit 1
fi

# Check  |to see if it exists and throw and error if it doesn't
#ls $fileName > /dev/null   # No need for this, you already checked above

while read line
do
    count= 'grep " | wc -m' 
    if [ "$count" < 2 ];then
        $line | tr -d '"' >> newFile.csv  #write to new file if condition meets
    fi 
done < ${filename}   # read from file line by line

#echo  $filename >> newFile.csv #This would print only the filename in the newfile.csv

exit

如何关闭bash脚本而不会出现意外的文件结尾？

1 个答案: