JAVA中的客户端/服务器表达式评估

时间:2014-03-09 11:10:37

标签: java parsing expression

我使用TCP创建了一个简单的客户端服务器应用程序。我正在使用eclipse,而且我对TCP很新,所以我的问题是: 1)如果我希望客户端发送一个表达式,如“10 + 20-5”,那么我把它放在参数中?这是arg [0]。 2)在发送上面提到的这样的表达式后,如何让服务器计算这个实际表达式,以便将结果返回给客户端“25”?

客户代码:

public class TCPClient {
public static void main (String args[]) { 
   // arguments supply message and hostname
    Socket s = null;
    try{
        int serverPort = 7896;
        s = new Socket(args[1],serverPort);

        DataInputStream in =new DataInputStream(s.getInputStream());
        DataOutputStream out = new DataOutputStream(s.getOutputStream());

        out.writeUTF(args[0]);
        String data = in.readUTF(); 
        System.out.println("Received: "+ data) ;
        }catch (UnknownHostException e) {System.out.println("Socket:"+e.getMessage());
        }catch (EOFException e){System.out.println("EOF:"+e.getMessage());
        }catch (IOException e){System.out.println("readline:"+e.getMessage());
        }finally {if(s!=null) 
        try {s.close(); 
        }catch (IOException e) {System.out.println ("close:" + e.getMessage());}
    }
}

}

服务器代码:

public class TCPServer {
public static void main (String args[]) {
    try{
        int serverPort = 7896; // the server port
        ServerSocket listenSocket = new ServerSocket(serverPort);
        while(true) {
        System.out.println("Server is ready and waiting for requests ... ");
            Socket clientSocket = listenSocket.accept();
            Connection c = new Connection(clientSocket);

        }
        } catch(IOException e) {System.out.println("Listensocket:"+e.getMessage());}
}
}

class Connection extends Thread {
DataInputStream in;
DataOutputStream out;
Socket clientSocket;

public Connection (Socket aClientSocket) {
        try {
        clientSocket = aClientSocket;
        in = new DataInputStream( clientSocket.getInputStream());
        out =new DataOutputStream( clientSocket.getOutputStream());

        this.start();
        } catch(IOException e) {System.out.println("Connection:"+e.getMessage());}
}

public void run(){
        try {   
            String data = in.readUTF();  
            out.writeUTF(data);
        }catch (EOFException e){System.out.println("EOF:"+e.getMessage());
        } catch(IOException e) {System.out.println("readline:"+e.getMessage());
        } finally{ try {clientSocket.close();}catch (IOException e){/*close failed*/}}
}
}

1 个答案:

答案 0 :(得分:0)

1 /在java中,当你通过java youclass_or_jar_file argument argument

然后,参数[0]将是您输入的第一个参数,而不是 C / C ++ 中的程序名称。因此在这种情况下,您可以使用格式为的参数向量 [host, port, "message"]。 然后在您的计划中,您只需发送arg[2] message

2 /要评估收到的表达式,您应该自己实施评估方法。

在这种方法中,我认为您应该将输入解析为postfix notation http://en.wikipedia.org/wiki/Reverse_Polish_notation,使用堆栈,阅读Wiki以获取更多信息,然后对其进行评估。< / p>

希望这个帮助