Question

编写一个程序，读取十个整数，并输出所有大于零的数字之和，所有数字之和小于零（将为负数或零），以及所有数字的总和数字，无论是正数，负数还是零。用户每次只输入十个数字，用户可以按任何顺序输入。您的程序不应要求用户分别输入正数和负数。现在修改这个程序，使它输出所有正数的总和，所有正数的平均值，所有非正数的总和，所有非正数的平均值，所有正数和非正数之和，以及输入的所有数字的平均值。

这就是我到目前为止......

#include <iostream>
using namespace std;
int main ()
{
     int number, negative_sum=0, positive_sum=0, sum=0, average_neg, 
         average_pos, average;
     int count=0, positiveCount=0, negativeCount=0; 

     cout << "Please Input 10 whole numbers(Each number should be separated by space or Enter)\n";
     for(int i=0; i < 10; i++)
     {
         cin >> number;

     if (number >= 0 )
     {
         positive_sum += number;
         positiveCount++;  
     } 
     else     
     {
         negative_sum += number ; 
         negativeCount++; 
     } 
     }

     average_pos = positive_sum / positiveCount;
     average_neg = negative_sum / negativeCount; 
     sum = positive_sum + negative_sum;
     average = sum / count; 

     cout << "The Total sum of Positive Numbers is " << positive_sum << " and the average of \nThe postive numbers entered is ";
     cout << average_pos<< endl; 
     cout << "The Total sum of Negative Numbers is " << negative_sum << " and the average of \nThe negative numbers entered is ";
     cout << average_neg << endl; 
     cout << "The Total sum of numbers entered is " << sum << " and its average is "<< average << endl;

     system("PAUSE");
     return 0;
}

基本上它只是打印＆＃34;请输入10个整数（每个数字应以空格或Enter分隔）\ n＆＃34;我输入数字后多次出现。

Answer 1

代码的问题在于行average_pos = positive_sum / positiveCount; average = sum / count;和average_neg = negative_sum / negativeCount;中出现零除以零除法。为了避免这种情况，您只能在if，positiveCount和negativeCount count

时添加执行除法的are greater than 0条件

此外，在您的代码中，您要将sum除以行count中的average = sum / count;，但代码中的count不会增加for。您的#include <iostream> using namespace std; int main () { int number, negative_sum=0, positive_sum=0, sum=0, average_neg=0, average_pos=0, average=0; int count=0, positiveCount=0, negativeCount=0; cout << "Please Input 10 whole numbers(Each number should be separated by space or Enter)\n"; for(int i=0;i<10;i++) { //cout<<"i is"<<i<<endl; cin >> number; if (number >= 0 ) { positive_sum += number; positiveCount++; count++; } else { negative_sum += number ; negativeCount++; count++; } } if(positiveCount>0) { average_pos = positive_sum / positiveCount; } if(negativeCount>0) { average_neg = negative_sum / negativeCount; } sum = positive_sum + negative_sum; if(count>0) { average = sum / count; } cout<<average_pos; cout << "The Total sum of Positive Numbers is " << positive_sum << " and the average of \nThe postive numbers entered is "; cout << average_pos<< endl; cout << "The Total sum of Negative Numbers is " << negative_sum << " and the average of \nThe negative numbers entered is "; cout << average_neg << endl; cout << "The Total sum of numbers entered is " << sum << " and its average is "<< average << endl; system("PAUSE"); return 0; }循环也提前结束。

正确的修改代码：

{{1}}

Answer 2

#include <iostream>
using namespace std;
int main ()
{
int number, negative_sum=0, positive_sum=0, sum=0, average_neg = 0,
average_pos = 0, average = 0;
int count=0, positiveCount=0, negativeCount=0;
cout << "Please Input 10 whole numbers(Each number should be separated by space or Enter)\n";
for(int i=0; i < 10; i++)
{
cin >> number;
if (number >= 0 )
{
positive_sum += number;
positiveCount++;
}
else
{
negative_sum += number ;
negativeCount++;
}
}
average_pos = positive_sum / positiveCount;
average_neg = negative_sum / negativeCount;
sum = positive_sum + negative_sum;
average = sum / count;
cout << "The Total sum of Positive Numbers is " << positive_sum << " and the average of \nThe postive numbers entered is ";
cout << average_pos<< endl;
cout << "The Total sum of Negative Numbers is " << negative_sum << " and the average of \nThe negative numbers entered is ";
cout << average_neg << endl;
cout << "The Total sum of numbers entered is " << sum << " and its average is "<< average << endl;
system("PAUSE");
return 0;
}

Answer 3

试试这个

#include <iostream>
using namespace std;
int main ()
{
     int number, negative_sum=0, positive_sum=0, sum=0, average_neg = 0, 
         average_pos = 0, average = 0;
     int count=0, positiveCount=0, negativeCount=0; 

 cout << "Please Input 10 whole numbers(Each number should be separated by space or Enter)\n";
  for(int i=0; i < 10; i++)
  {
     cin >> number;
     if (number >= 0 )
     {
         positive_sum += number;
         positiveCount++;  
     } 
     else     
     {
         negative_sum += number ; 
         negativeCount++; 
     } 
  }
  average_pos = positive_sum / positiveCount;
  average_neg = negative_sum / negativeCount; 
  sum = positive_sum + negative_sum;
  average = sum / count; 

 cout << "The Total sum of Positive Numbers is " << positive_sum << " and the average of \nThe postive numbers entered is ";
 cout << average_pos<< endl; 
 cout << "The Total sum of Negative Numbers is " << negative_sum << " and the average of \nThe negative numbers entered is ";
 cout << average_neg << endl; 
 cout << "The Total sum of numbers entered is " << sum << " and its average is "<< average << endl;

 system("PAUSE");
 return 0;
}

希望这有助于......：）

C ++;编写一个读入十个整数的程序

3 个答案: