如何将JavaFX与Java Swing应用程序集成?

时间:2014-03-09 06:20:21

标签: java swing javafx javafx-2

我想创建一个扩展JFXPanel以处理折线图的类,并将此JFXPanel与我在Java SE中创建的应用程序集成,我还可以从我的JFrame应用程序实时将数据传递给图形。

这是我的示例代码:

    public class LineChartJFXPanel extends JFXPanel {

        private final LineChart<Number,Number> chart;
        private final HashMap<String,  XYChart.Series<Number,Number>> series;
        private final NumberAxis xAxis, yAxis;

        public LineChartJFXPanel() {
            Platform.setImplicitExit(false);
            series = new HashMap<>();
            xAxis = new NumberAxis(0.0,10.0,1.0);
            yAxis = new NumberAxis(0.0,10.0,1.0);
            chart = new LineChart<>(xAxis,yAxis);
            setScene(new Scene(chart));
        }

        public void setSeries(String idSeries, String nameSeries, Number xIni, Number yIni){
            XYChart.Series<Number,Number> newSeries = new XYChart.Series<>();
            newSeries.setName(nameSeries);
            newSeries.getData().add(new XYChart.Data<>(xIni,yIni));
            chart.getData().add(newSeries);
            series.put(idSeries, newSeries);
        }
    }

******************************************

    public class PanelChart extends JPanel{

        LineChartJFXPanel lineChart;

        public PanelChart(){
            setLayout(new GridLayout(1, 2));
            lineChart =  new LineChartJFXPanel();
            add(lineChart);
        }
    }


********************************

    public class Main extends JFrame{
        PanelChart chartPanel;
        public Main(){
            setPreferredSize(new Dimension(800, 600));
            chartPanel = new PanelChart();
            getContentPane().add(chartPanel);
            setVisible(true);
        }

        public static void main(String args[]){
            Main main = new Main();
            main.setVisible(true);
        }

    }

但是当我运行代码时,它会显示以下错误:

Exception in thread "main" java.lang.IllegalStateException: Not on FX application thread; currentThread = main

at com.sun.javafx.tk.Toolkit.checkFxUserThread(Toolkit.java:237)
at com.sun.javafx.tk.quantum.QuantumToolkit.checkFxUserThread(QuantumToolkit.java:400)
at javafx.scene.Scene.<init>(Scene.java:290)
at javafx.scene.Scene.<init>(Scene.java:198)
at javachartdemo.LineChartJFXPanel.<init>(LineChartJFXPanel.java:39)
at javachartdemo.PanelChart.<init>(PanelChart.java:22)
at javachartdemo.Main.<init>(Main.java:21)
at javachartdemo.Main.main(Main.java:27)

我的申请需要更改什么?

2 个答案:

答案 0 :(得分:2)

错误消息告诉您必须在FX应用程序线程中运行触及JavaFX的所有内容,因为JavaFX不是线程安全的。

要在该线程上执行某些操作,请使用Platform.runLater

请注意,Swing有一个类似的限制,区别在于没有任何东西会抛出异常。相反,你迟早会得到奇怪的行为。对于SwingUtilities.invokeLater

答案 1 :(得分:0)

需要在JavaFX应用程序线程上发生Scene对象和调用JFXPanel.setScene,如下所示:

Platform.runLater(() -> {
  setScene(new Scene(chart));
});