Question

好吧，伙计们！写入文件时遇到问题。基本上，我的问题是，当我写入文件时，例如变量2913 Harvey Drive中的person.address1等地址将被写入文件中的单独行而不是一行。我需要他们在一条线上。我做了一些研究，找不到任何我理解的东西，所以我希望我能有一个例子，因为它与我的代码有关，以帮助我理解。这是我的代码：

int newEntry()
{
string str;
Client person;
char response;
double temp1;
double temp2;
ostringstream strs1;
ostringstream strs2;

//create file object and open file
fstream customer("customer.dat", ios:: out | ios::app);

if (!customer)
{
    cout << "Error opening file. Program aborting." << endl;
}

do
{
    cout << "Enter client information:" << endl << endl;
    cout << "Name:               ";
    cin  >> person.name;
    cout << endl;

    cout << "Address 1:          ";
    cin  >> person.address1;
    cout << endl;

    cout << "Address 2:          ";
    cin  >> person.address2;
    cout << endl;

    cout << "Phone:              ";
    cin  >> person.phone;
    cout << endl;

    cout << "Acct. Balance:      ";
    cin  >> temp1;
    strs1 << temp1;
    str = strs1.str();
    person.acctBal = str;
    cout << endl;

    cout << "Last Payment:       ";
    cin  >> temp2;
    strs2 << temp2;
    str = strs2.str();
    person.lastPay = str;
    cout << endl;

    customer << person.name << endl;
    customer << person.address1 << endl;
    customer << person.address2 << endl;
    customer << person.phone << endl;
    customer << person.acctBal << endl;
    customer << person.lastPay << endl;
    customer << endl;       //blank space in file

    cout << endl << "Do you want to enter another record? (Enter Y for Yes, N 
                             for No):   ";
    cin  >> response;
    //add validation to make sure they enter y or n
    cout << endl << endl;
    cout << BORDER << endl << endl;


} while (toupper(response) == 'Y');

customer.close();

return 1;
}

我看到连接字符串变量然后将ENTIRE字符串变量保存到文件中的内容，但我不确定我是否会理解如何读取每一行。这是读取代码的函数：

int displayAll()
{
vector<Client> store;
string space;
Client foo;
int i = 0;

fstream customer("customer.dat", ios::in);

if (!customer)
{
    cout << "Error opening file. Program aborting." << endl;
    return 0;
}

while (!customer.eof())
{
    store.push_back(foo);

    customer >> store[i].name;
    customer >> store[i].address1;
    customer >> store[i].address2;
    customer >> store[i].phone;
    customer >> store[i].acctBal;
    customer >> store[i].lastPay;
    customer >> space;

    i++;
}

for (int k = 0; k < i; k++)
{
    cout << "   Name:               " << store[k].name << endl
         << "   Address 1:          " << store[k].address1 << endl
         << "   Address 2:          " << store[k].address2 << endl
         << "   Phone:              " << store[k].phone << endl
         << "   Acct. Balance:      " << store[k].acctBal << endl
         << "   Last Payment:       " << store[k].lastPay << endl << endl;
}

cout << BORDER << endl << endl;

customer.close();
return 1;

}

因此，如果我使用了连接方法，例如：

string += person.name; string += newLine; //newLine would be a variable holding the endl function string += person.address;

（我不确定我是否理解上述代码及其工作原理，或者我是否做得对。）然后将string变量保存到文件中，customer >> store[i].name会存储整行还是直到有空格？

Answer 1

使用空格输入字符串：

 #include <stdio.h>

int main()
{
 char string [256];
 printf ("Insert your full address: ");
 gets (string);     // warning: unsafe (see fgets instead)
 printf ("Your address is: %s\n",string);
 return 0;

}

concat String Like：

#include <stdio.h>
#include <string.h>

 int main ()
{
char str[80];
strcpy (str,"these ");
strcat (str,"strings ");
strcat (str,"are ");
strcat (str,"concatenated.");
puts (str);
return 0;

}

无法将整行的字符串写入文件

1 个答案: