我一直在寻找我的问题背后的原因无济于事。它在我添加异常处理程序之前工作,所以我相对困惑。我是python,JSON,API和sql的新手,但不是编程。
def getSyllables(word):
conn = sqlite3.connect("wordbase.db")
c = conn.cursor()
c.execute('SELECT * FROM words WHERE Word =?', [word])
syllables = 0
if (c.fetchone() == None):
url = 'http://rhymebrain.com/talk?function=getWordInfo&word=' + word
try:
r = requests.get(url)
j = json.loads(r.text)
rememberSyllables(word, int(j['syllables'])
syllables = int(j['syllables'])
except requests.exceptions.RequestException as e:
syllables = 0
else:
syllables = c.fetchone[1]
return syllables
我现在得到的错误是:
syllables = int(j['syllables'])
^
SyntaxError: invalid syntax
如果我删除它(即使我很确定语法是正确的吗?):
except requests.exceptions.RequestException:
^
SyntaxError: invalid syntax
`
答案 0 :(得分:1)
问题很简单,你还没有关闭前一行的括号:
rememberSyllables(word, int(j['syllables']))
这应该可以解决问题。
答案 1 :(得分:1)
rememberSyllables(word, int(j['syllables']))
这里额外的)会解决问题!!