Question

所以我的主要计划是使用带有按钮的GUI和两个jTextFields。按下按钮时，它会启动我所做的Runnah类的新线程。假设Runnah类从文本字段中获取输入;

当我运行Runnah

时，NumberFormatException班级会获得gui.getSeconds();

MainGUI类

public class MainGUI extends javax.swing.JFrame {

Runnah runnah;
Thread thread;

public MainGUI() {
    initComponents();
    //runnah = new Runnah();
}                        

private void startButtonActionPerformed(java.awt.event.ActionEvent evt) {                                            
    try {
        runnah = new Runnah();
    } catch (AWTException ex) {
        Logger.getLogger(MainGUI.class.getName()).log(Level.SEVERE, null, ex);
    }
    thread = new Thread(runnah);
    thread.start();
}                                           

public String getInput(){
    String temp = textInp.getText();
    return temp;
}
public int getSeconds(){
    return Integer.parseInt(secInp.getText());
}

/**
 * @param args the command line arguments
 */
public static void main(String args[]) {
    /* Create and display the form */
    java.awt.EventQueue.invokeLater(new Runnable() {
        public void run() {
                new MainGUI().setVisible(true);
        }
    });
}
// Variables declaration - do not modify                     
private javax.swing.JTextField secInp;
private javax.swing.JButton startButton;
private javax.swing.JTextField textInp;
// End of variables declaration                   
}

Runnah Class

public class Runnah implements Runnable{

private MainGUI gui;

private Robot robot;

public Runnah() throws AWTException{
    this.robot = new Robot();
    gui = new MainGUI();
}

public Runnah(Robot robot) {
    this.robot = robot;
}

@Override
public void run() {

    String temp = gui.getInput();
    CharSequence input = temp;
    int seconds = 1;
    seconds = gui.getSeconds() * 1000;

    robot.delay(seconds);
}

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Answer 1

我刚才没有引用现有的MainGUI类。

线程“Thread-3”中的异常java.lang.NumberFormatException：对于输入字符串：“”

1 个答案: