PHP Soap复杂数据类型?

时间:2014-03-08 15:12:09

标签: php web-services soap

我正在尝试使用PHP Soap服务但是我似乎遇到了复杂/抽象类型的问题。

这是使用SOAP UI生成的SOAP调用: -

 <soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:lin="http://llu.webservices.opalonline.co.uk/LineCharacteristicsWS">
   <soapenv:Header/>
   <soapenv:Body>
      <lin:GetLineCharacteristics>
         <lin:request>
            <!--Optional:-->
            <lin:UserCredentials>
               <!--Optional:-->

               <!--Optional:-->
               <lin:Username>testUser</lin:Username>
               <lin:Password>testPass</lin:Password><lin:AgentID>1234</lin:AgentID>
            </lin:UserCredentials>
            <lin:RequestDetails xsi:type="lin:TelephoneNumberRequest" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
                <lin:TelephoneNumber>123456789</lin:TelephoneNumber>
            </lin:RequestDetails>
            <lin:UserConsent>Yes</lin:UserConsent>
            <lin:ServiceType>MPF</lin:ServiceType>
         </lin:request>
      </lin:GetLineCharacteristics>
   </soapenv:Body>
</soapenv:Envelope>

这是我的PHP代码: -

$call = new StdClass();

$call->request =  new StdClass();
$call->request->UserConsent = "Yes";
$call->request->ServiceType = "MPF";

$call->request->UserCredentials =  new StdClass();
$call->request->UserCredentials->Username="testUser";
$call->request->UserCredentials->Password="testPass";
$call->request->UserCredentials->AgentID=1234;


$call->request->RequestDetails = new StdClass();
$call->request->RequestDetails->TelephoneNumber = "123456789";

$url = "https://llu.webservices.opalonline.co.uk/LineCharacteristicsWSV6/LineCharacteristicsWS.asmx?wsdl";
$client = new SoapClient($url, array('trace' => 1, exceptions=> 1,'soap_version' => SOAP_1_1));

$result = $client->GetLineCharacteristics($call);

echo $client->__getLastRequest();
echo $client->__getLastResponse();

运行代码时,会生成以下错误: -

  

致命错误:未捕获的SoapFault异常:[soap:Client]服务器无法读取请求。 ---&GT; XML文档中存在错误(2,382)。 ---&GT;指定的类型是abstract:name ='RequestType',namespace ='http://llu.webservices.opalonline.co.uk/LineCharacteristicsWS',位于http://llu.webservices.opalonline.co.uk/LineCharacteristicsWS'>。在/Users/jamesormerod/NetBeansProjects/fpdfDev/TestClass.php:23

有人可以帮忙吗?

1 个答案:

答案 0 :(得分:0)

为了能够使用正确的类型和命名空间发送格式良好的请求,必须使用命名为必需元素的类和将元素映射到类的类映射。 WsdlToPhp项目可以帮助您生成类和类图。您可以在wsdltophp.com使用该项目。

然后,如果您生成名为LineCharacteristics的包,您将能够使用此示例代码发送请求:

$lineCharacteristicsServiceGet = new LineCharacteristicsServiceGet(); // sample call for LineCharacteristicsServiceGet::GetLineCharacteristics() $details = new LineCharacteristicsStructTelephoneNumberRequest('+3363136363636'); $request = new LineCharacteristicsStructGetLineCharacteristicsRequest($details, LineCharacteristicsEnumUserConsentEnum::VALUE_YES, LineCharacteristicsEnumServiceTypeEnum::VALUE_MPF); $userCredentials = new LineCharacteristicsStructCredentials(11111,'********','********'); $request->setUserCredentials($userCredentials); $characteristics = new LineCharacteristicsStructGetLineCharacteristics($request); $r = $lineCharacteristicsServiceGet->GetLineCharacteristics($characteristics); echo implode("\r\n", array($lineCharacteristicsServiceGet->getLastRequestHeaders(),$lineCharacteristicsServiceGet->getLastRequest(),$lineCharacteristicsServiceGet->getLastResponseHeaders(),$lineCharacteristicsServiceGet->getLastResponse())); if($r) print_r($lineCharacteristicsServiceGet->getResult()); else print_r($lineCharacteristicsServiceGet->getLastError());