我可以使用相同的图片发送两封电子邮件,但不能发送存储在MySQL表中的所需MySQL数据a
和b
。两封电子邮件中只显示了相同的数据a
。
如何发送包含不同数据的每封电子邮件,即第一个数据a
和第二个b
?
这是我的代码:
<?php
$con=mysqli_connect("localhost","586729","xxxxxxxx","586729");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$i=1;
$result = mysqli_query($con,"SELECT * FROM db");
while($row = mysqli_fetch_array($result))
{
$s[$i] = $row['sch name'];
$i=$i+1;
}
mysqli_close($con);
$i=2;
while($i>=1)
{
$to = 'woshicdg@gmail.com';
$subject = 'PHP Mail Attachment Test';
$bound_text = "jimmyP123";
$bound = "--".$bound_text."\r\n";
$bound_last = "--".$bound_text."--\r\n";
$headers = "From: admin@server.com\r\n";
$headers .= "MIME-Version: 1.0\r\n"
."Content-Type: multipart/mixed; boundary=\"$bound_text\"";
$message .= "If you can see this MIME than your client doesn't accept MIME types!\r\n"
.$bound;
$message .= "Content-Type: text/html; charset=\"iso-8859-1\"\r\n"
."Content-Transfer-Encoding: 7bit\r\n\r\n"
."The short form of the school name ".$s[$i]." is shown now.\r\n"
.$bound;
$file = file_get_contents("http://hkalextsui.freevar.com/machu.JPG");
$message .= "Content-Type: image/jpg; name=\"regal_004.jpg\"\r\n"
."Content-Transfer-Encoding: base64\r\n"
."Content-disposition: attachment; file=\"regal_004.jpg\"\r\n"
."\r\n"
.chunk_split(base64_encode($file))
.$bound_last;
if(mail($to, $subject, $message, $headers))
{
echo 'MAIL SENT';
}
else
{
echo 'MAIL FAILED';
}
$i=$i-1;
}
?>