如何同时计算三幅图像的总像素? 我尝试使用java Swing Worker和Thread,我得到了答案,但需要1.30分钟才能返回指定范围的总像素数(每张图像30秒,图像大小480 * 303)。但我需要在30秒内同时获得三张图像的答案。
public class ImageProcessor1 implements Runnable{
static int blackPix=0;
BufferedImage tempImg;
public static int blackPixel=0;
public ImageProcessor1(String path) throws Exception{
tempImg = ImageIO.read(new File(path));
}
private static int[] getPixelData(BufferedImage img, int x, int y) {
int argb = img.getRGB(x, y);
int rgb[] = new int[]{
(argb >> 16) & 0xff, //red
(argb >> 8) & 0xff, //green
(argb) & 0xff //blue
};
System.out.println("Process1 :rgb: " + rgb[0] + " " + rgb[1] + " " + rgb[2]);
return rgb;
}
@Override
public void run() {
int[][] pixelData = new int[tempImg.getHeight() * tempImg.getWidth()][3];
int[] rgb;
int height=tempImg.getHeight();
int width=tempImg.getWidth();
int counter = 0;
for (int i = 0; i < width; i++) {
for (int j = 0; j < height; j++) {
rgb = getPixelData(tempImg, i, j);
if(rgb[0]<125 && rgb[0]>105 && rgb[1]<125 && rgb[1]>105 && rgb[2]<125 && rgb[2]>105)
{
blackPixel+=1;
}
}
}
}
}
答案 0 :(得分:1)
非常奇怪的是,迭代这么小的图片需要30秒!
在进行一些分析之后,似乎在热循环中使用println语句会大大减慢你的速度。
在对代码进行少量修改后,我的机器上的10500x5788图像需要大约3秒。
修改后的版本:
package application;
import java.awt.image.BufferedImage;
import java.io.File;
import java.util.concurrent.TimeUnit;
import javax.imageio.ImageIO;
public class ImageProcessor1 implements Runnable {
BufferedImage tempImg;
public static int blackPixel = 0;
public ImageProcessor1(final String path) throws Exception {
final long start = System.nanoTime();
tempImg = ImageIO.read(new File(path));
// Use tracing, profiling and sampling to proof performance issues and fixes
System.out.println("ImageIO took " + TimeUnit.NANOSECONDS.toMillis(System.nanoTime() - start)
+ " ms.");
}
@Override
public void run() {
long start = System.nanoTime();
final int height = tempImg.getHeight();
System.out.println("Getting height '" + height + "' took "
+ TimeUnit.NANOSECONDS.toMillis(System.nanoTime() - start) + " ms.");
start = System.nanoTime();
final int width = tempImg.getWidth();
System.out.println("Getting width '" + width + "' took "
+ TimeUnit.NANOSECONDS.toMillis(System.nanoTime() - start) + " ms.");
start = System.nanoTime();
// reuse variables
int argb;
int red;
int green;
int blue;
for (int i = 0; i < width; i++) {
for (int j = 0; j < height; j++) {
// HOT LOOP. Do as little as possible. No println calls!
argb = tempImg.getRGB(i, j);
// inline all method calls
red = argb >> 16 & 0xff; // red
green = argb >> 8 & 0xff; // green
blue = argb & 0xff; // blue
if (red < 125 && red > 105 && green < 125 && green > 105 && blue < 125 && blue > 105) {
blackPixel += 1;
}
}
}
System.out.println("Iterating pixels took "
+ TimeUnit.NANOSECONDS.toMillis(System.nanoTime() - start) + " ms.");
}
public static void main(final String[] args) throws Exception {
new ImageProcessor1("big.jpg").run();
System.out.println("Number of blackpixels = " + blackPixel);
}
}
更一般地说,您必须小心您的方法,因为您将所有图像读入RAM,然后进行处理。如果您同时使用3个或更多大图像,则可能会出现OutOfMemoryError。如果这成为问题,您可以将图像作为输入流读取,并且一次只处理图像的小缓冲区。
要了解如何做到这一点,请参阅http://imagej.nih.gov/ij/source/ij/io/ImageReader.java。
要了解如何累积多个线程的输出,请参阅How write mulithreaded code and accumulate the output from all the threads in a single file。