Question

我需要删除包含a-Z，0-9或符号《，》，【或{{1}的所有行}来自文件，但只有在大括号（】和{）内的某处找到它们，也可以在同一行找到。

例如，取样本文件：

第1行和第2行将被删除，因为Once {upon} a time, there lived an owl. The owl lived in a {forest with 10,000 trees.} One day, the owl said, "I like to eat mice." So the owl ate {10,000} mice. The owl said, {“吃饱了！”} Then{,} the owl rested. The next day, he read the book, 《水滸傳》. He enjoyed it so much, that he read {《水滸傳》} again the next day.的项目位于大括号之间。
第4行（和第2行）将被删除，因为数字位于大括号之间。
第8行将被删除，因为a-Z存在并且在大括号内。
其他行会被忽略，因为他们都没有将这些项放在《和{括号之间。

我尝试制作这个BASH脚本，但在仔细检查输出后，找到了一些不起作用的实例：

大括号永远不会嵌套。
大括号永远不会分开。

为什么我的sed '/{.*[a-Z0-9《》【】].*}/d' input.txt > output.txt脚本无法正确删除包含sed，a-Z，0-9，《，》的所有行，或者在大括号之间找到【

Answer 1

您的角色类不正确[a-Z]。它应该是[a-z]或[A-Z]或两者[a-zA-Z]。

sed '/{[^}]*[a-zA-Z0-9《》【】][^}]*}/d' file

$ cat file
Once {upon} a time, there lived an owl.
The owl lived in a {forest with 10,000 trees.}
One day, the owl said, "I like to eat mice."
So the owl ate {10,000} mice.
The owl said, {“吃饱了！”}
Then{,} the owl rested.
The next day, he read the book, 《水滸傳》.
He enjoyed it so much, that he read {《水滸傳》} again the next day.

$ sed '/{[^}]*[a-zA-Z0-9《》【】][^}]*}/d' file
One day, the owl said, "I like to eat mice."
The owl said, {“吃饱了！”}
Then{,} the owl rested.
The next day, he read the book, 《水滸傳》.

如何删除包含模式`{。* [a-Z0-9“”【】]的行。*}`用sed？

1 个答案: