PDO搜索引擎?

时间:2014-03-08 00:48:42

标签: php mysql pdo

在我重写PDO之前,我为我的网站创建了一个搜索功能。对于使用MySQL数据库而言,我对PHP和PDO都是一个非常新的东西,我不知道如何将这段代码翻译成PDO。我很感激有人稍微跟我说话,以帮助我学习。

我目前的代码是:

function doSearch() {
    $output = '';
    if(isset($_POST['search'])) {
        $searchq = $_POST['search'];
        $searchq = preg_replace ("#[^0-9a-z]#i","",$searchq);
        $sql = "SELECT * FROM entries WHERE name LIKE '%$searchq%' or description LIKE '%$searchq%' or content LIKE '%$searchq%'";
        $query = mysqli_query($connect, $sql);
        $count = mysqli_num_rows($query);
        if($count == 0) {
            $output = '<tr><tr>No results found.</tr></td>';
        } else {
            while($row = mysqli_fetch_array($query)) {
                $eName = $row['name'];
                $eDesc = $row['description'];
                $eCont = $row['content'];
                $id = $row['id'];
                $elvl = $row['level'];
                $ehp = $row['hp'];

                $output .= '<tr><td><a href="http://xxxx.com/xxx?id=' .$id. '" onclick="document.linkform.submit();">'.$eName.'</a></td><td>'.$eDesc.'</td><td>'.$elvl.'</td><td>'.$ehp.'</td></tr>';
            }
        }
    return $output;
    }
 }

已经建立了PDO连接,似乎是成功的。这是在我的functions.php文件中,我的connection.php文件已附加到functions.php。

提前致谢!

1 个答案:

答案 0 :(得分:1)

应该是

 $conn='';  
    try { 
         $conn = new PDO('mysql:host=localhost;dbname=xxx', 'xxx', 'xxx');
 } 
catch (PDOException $e) { 
exit('Database error.'); 
} 
$sql = "SELECT * FROM entries WHERE name LIKE :searchq or description LIKE :searchq or content LIKE :searchq";

$stmt = $conn->prepare($sql);
$stmt->bindParam(":searchq",$searchq,PDO::PARAM_STR);
$stmt->execute();
$count = $stmt->rowCount();
 if($count == 0) {
            $output = '<tr><tr>No results found.</tr></td>';
        } else {
            while($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
                $eName = $row['name'];
                $eDesc = $row['description'];
                $eCont = $row['content'];
                $id = $row['id'];
                $elvl = $row['level'];
                $ehp = $row['hp'];

                $output .= '<tr><td><a href="http://xxxx.com/xxx?id=' .$id. '" onclick="document.linkform.submit();">'.$eName.'</a></td><td>'.$eDesc.'</td><td>'.$elvl.'</td><td>'.$ehp.'</td></tr>';
            }
        }