Question

我知道这是一个很长的问题..但是我在这里试图学习解析XML文档的众多方法之一......我在网上的很多例子都是非常简单的XML文档..但是我有一些多层次的东西，我想解析它..

<?xml version="1.0" encoding="utf-8"?>
<PageList>
    <Page>
        <UpperLeft>
            <Parameters>
                <League>AL</League>
                <Season>R</Season>
                <Category>Runs</Category>
                <RankOrder>n/a</RankOrder>
            </Parameters>
            <Info>
                <Row1>
                    <TeamLogo>LAA.tif</TeamLogo>
                    <Rank>1.</Rank>
                    <Name>Trout</Name>
                    <Stat>109</Stat>
                </Row1>
                <Row2>
                  .
                  .
                  .
                </Row5>
            </Info>
        </UpperLeft>
        <UpperRight>
            .
            .
            .
        </UpperRight>
        <LowerLeft>
            .
            .
        </LowerLeft>
        <LowerRight>
            .
            .
        </LowerRight>
    </Page>
</PageList>

几乎会有很多页面..我不想粘贴完整的东西，所以我试图将其剪掉..但这是结构：

page
  --> upper left
      --> parameters
          --> league
          --> season
          --> category
          --> rankorder
      --> info
          --> row 1
              --> team logo
              --> rank
              --> name
              --> stat
          --> row 2 to row 5
  --> upper right, lower left, lower right
end page

我怎样才能成功解析这场噩梦？一切都是我创造的一个很好，很整洁的课程......但是试着将所有东西都放回到课堂上，我只是遇到了这么多麻烦..

XDocument xdoc;
        try
        {
            List<MLBPage> collection =
            {
                from e in XDocument.Load("PageList.xml").Root.Elements("PageList")

                select new MLBPage
                {
                    ul = new Quadrant  //upper left
                    {
                        qp = new QuadrantParameters
                        {
                            //league, season, category, rank order here
                        },
                        qi = new QuadrantInfo
                        {
                            //team logo, rank, name, stat here
                        }
                    }
                }
            }
        }
        catch (Exception)
        {
            /

Answer 1

您可以开始映射classes / attributes / elements：

[Serializable] //Root
[XmlRoot(ElementName = "InfXml", Namespace="the namespace URI")]
public class InfXml
{
    [XmlAttribute(AttributeName = "id")] //attribute
    public string Id { get; set; }
    public bool ShouldSerializeId() //Should serialize, only serializes if not null.
    {
        return !string.IsNullOrEmpty(Id); //This is only for optional fields.
    }

    [XmlElement(ElementName = "Identification")] //Non optional group.
    public Identification Identification{ get; set; }

    [XmlElement(ElementName = "Adress")] //Optional group.
    public Adress Adress{ get; set; }
    public bool ShouldSerializeAdress()
    {
        return Adress!= null;
    }
}

如果你有一个映射的class-to-Xml，你可以使用这两种方法：

const string PrefixXml = "<?xml version=\"1.0\" encoding=\"utf-8\" ?>";

public static object Deserialize<T>(T obj, string xmlText)
{
    try
    {
        XmlSerializer deserializer = new XmlSerializer(typeof(T));
        TextReader textReader = new StringReader(xmlText);
        return (T)deserializer.Deserialize(textReader);
    }
    catch (Exception ex)
    {
        //Catch here.
        return null;
    }

}

public static XmlDocument Serialize<T>(T obj)
{
    string xmlString = GerarXml.Gerar<T>(obj);
    if (!xmlString.Contains("xml version="))
    {
        xmlString = PrefixXml + xmlString;
    }
    xmlString = xmlString.Replace(Environment.NewLine, string.Empty);
    XmlDocument doc = new XmlDocument();
    doc.LoadXml(xmlString);
    return doc;
}

如果您想将XML作为字符串获取：

public static string GetXmlText(XmlDocument doc)
{
    StringWriter stringWriter = new StringWriter();
    XmlTextWriter xmlTextWriter = new XmlTextWriter(stringWriter);

    doc.WriteTo(xmlTextWriter);

    string ret = stringWriter.ToString();

    ret = ret.Replace(Environment.NewLine, string.Empty);
    if (!ret.Contains("xml version="))
    {
        return PrefixXml + ret;
    }
    return ret;

}

解析具有许多不同级别的XML文件的最简单方法是什么？

1 个答案: