这是我的桌子。
这是我到目前为止所做的一切,但是......唯一的问题是我还需要more_info列的总数。我该怎么做呢?
SELECT *, SUM(hit_count) as 'view_count'
FROM $table_name
WHERE create_date >='".$fromdate."'
AND create_date<='".$todate."'
AND post_author ='".$_POST['pps_user_id']."'
GROUP BY post_id desc
我们得到的是hit_count的总数,但是我也希望得到more_info区域中每个不同的jsn字符串的总数,并且当通过post_id desc分组时也输出
答案 0 :(得分:0)
不确定这是否回答了您的问题,但您可以使用SUBSTRING_INDEX解析这些值,如下所示
SELECT post_id,jsn_string,SUM(jsn_count) as jsn_count
FROM
(SELECT post_id,
SUBSTRING_INDEX(SUBSTRING_INDEX(more_info,'"',4),'"',-1) as jsn_string,
SUBSTRING_INDEX(more_info,':',-3) + 0 as jsn_count
FROM yourtable
UNION All
SELECT post_id,
SUBSTRING_INDEX(SUBSTRING_INDEX(more_info,'"',8),'"',-1) as jsn_string,
SUBSTRING_INDEX(more_info,':',-1) + 0 as jsn_count
FROM yourtable
)T1
WHERE jsn_string != ''
GROUP BY post_id,jsn_string