使用Ionic framework,我正在尝试创建一组三个按钮作为单选按钮:
如果我点击早餐,我希望午餐和晚餐回归正常(白色)状态,早餐转为蓝色。
使用我当前的代码,我无法使用此功能,虽然我可以让按钮切换颜色,稍微随机(也许我只是不理解ng-class
指令)。
这是我的HTML代码:
<div class="bar bar-subheader">
<div class="button-bar">
<a class="button" ng-class="{'button-positive' : !isActiveB, 'none': isActiveB}" ng-click="active('breakfast')">Breakfast</a>
<a class="button" ng-class="{'button-positive' : !isActiveL, 'none': isActiveL}" ng-click="active('lunch')">Lunch</a>
<a class="button" ng-class="{'button-positive' : !isActiveD, 'none': isActiveD}" ng-click="active('dinner')">Dinner</a>
</div>
</div>
我的JS:
$scope.active = function(meal) {
switch (meal) {
case 'breakfast':
$scope.$broadcast('slideBox.setSlide', 0);
$scope.isActiveB = $scope.isActiveB;
$scope.isActiveL = !$scope.isActiveL;
$scope.isActiveD = !$scope.isActiveD;
break;
case 'lunch':
$scope.$broadcast('slideBox.setSlide', 1);
$scope.isActiveB = !$scope.isActiveB;
$scope.isActiveL = $scope.isActiveL;
$scope.isActiveD = !$scope.isActiveD;
break;
case 'dinner':
$scope.$broadcast('slideBox.setSlide', 2);
$scope.isActiveB = !$scope.isActiveB;
$scope.isActiveL = !$scope.isActiveL;
$scope.isActiveD = $scope.isActiveD;
break;
}
};
如果您需要更多信息和工作解决方案,我可以将代码放在JSFidle中。
感谢您的帮助。
注意:我想维护我的active()
函数,并尽可能使用ng-class
指令,因为我还有很多依赖于此函数的其他代码。
答案 0 :(得分:26)
也许这个简化的例子会对你有所帮助:
angular.module('plunker', []).controller('MainCtrl', function($scope) {
$scope.active = 'breakfast';
$scope.setActive = function(type) {
$scope.active = type;
};
$scope.isActive = function(type) {
return type === $scope.active;
};
});
<link rel="stylesheet" href="http://code.ionicframework.com/0.9.26/css/ionic.min.css">
<script src="http://code.angularjs.org/1.2.13/angular.js"></script>
<div ng-app="plunker" ng-controller="MainCtrl" class="bar bar-subheader">
<div class="button-bar">
<a class="button" ng-class="{'button-positive': isActive('breakfast')}" ng-click="setActive('breakfast')">Breakfast</a>
<a class="button" ng-class="{'button-positive': isActive('lunch')}" ng-click="setActive('lunch')">Lunch</a>
<a class="button" ng-class="{'button-positive': isActive('dinner')}" ng-click="setActive('dinner')">Dinner</a>
</div>
</div>
答案 1 :(得分:6)
这是针对未来Google员工的更灵活的解决方案。
工作人员: http://plnkr.co/edit/U2Hvx4?p=preview
.directive('barSelect',function($parse){
return {
restrict: 'A',
require: 'ngModel',
scope: {
model: '=ngModel',
value: '=barSelect'
},
link: function(scope, element, attrs, ngModelCtrl){
element.addClass('button');
element.on('click', function(e){
scope.$apply(function(){
ngModelCtrl.$setViewValue(scope.value);
});
});
scope.$watch('model', function(newVal){
element.removeClass('active');
if (newVal === scope.value){
element.addClass('active');
}
});
}
};
});
一个用法示例:
<div class="button-bar">
<a bar-select="button.value"
ng-repeat="button in clientSideList"
ng-model="data.clientSide"
>{{button.text}}</a>
</div>
答案 2 :(得分:0)
这是另一种替代方法,它将其他两种方法结合在一起。它只需要一个&lt; button-group&gt;具有以下属性的元素:
.directive('buttonGroup',function($parse){
return {
restrict: 'E',
require: 'ngModel',
scope: {
model: '=ngModel',
buttons: '=',
buttonClass: '='
},
template: '<a class="group-btn {{buttonClass}}" ' +
' ng-repeat="button in buttons" ' +
' ng-class="{\'group-btn-active\': isActive(button.value)}" ' +
' ng-click="buttonClicked(button.value)"> ' +
' {{button.text}} ' +
'</a>',
controller: ['$scope', function($scope) {
$scope.buttonClicked = function(value) {
$scope.value = value;
};
$scope.isActive = function(value) {
return $scope.value === value;
};
}],
link: function(scope, element, attrs, ngModel) {
element.on('click', function(e){
scope.$apply(function(){
ngModel.$setViewValue(scope.value);
});
});
scope.$watch('model', function(newVal){
scope.value = newVal;
});
}
};
})
示例用法:
<button-group ng-model="sortOrder" buttons="sortOptions"
button-class="'md-button my-other-class'"></button-group>
其中sortOptions是表单的数组:
$scope.sortOptions = [
{ value: 'priority', text: 'Priority' },
{ value: 'duration', text: 'Call Duration' }
];