总和数据行

Question

当检查号码相同时，我正试图将数据行数加到Sum。

select
 chkdetail_t.check_acct,
 chkheader_t.acct_number,
 chkdetail_t.check_number,
  SUM(CASE WHEN chkdetail_t.check_number = chkdetail_t.check_number THEN  chkdetail_t.amount ELSE NULL END)  AS chek_total,
 convert(VARCHAR(10),CAST(chkdetail_t.check_date as datetime), 101) AS chk_date,
 chkdetail_t.amount,
 chkdetail_t.vend_name,
 chkdetail_t.chk_status,
 chkdetail_t.reconsiled,
 chkdetail_t.chk_type


 from dbo.chkdetail_t
 join dbo.chkheader_t
 on chkheader_t.check_acct = chkdetail_t.check_acct


 where chkdetail_t.check_acct = 'HUNTINGTON'
 and chkdetail_t.chk_status not in ('V', 'R')
 and chkdetail_t.chk_type != 'R'
 and chkdetail_t.reconsiled = 0

 group by chkdetail_t.check_acct,
chkheader_t.acct_number, 
chkdetail_t.check_number, 
chkdetail_t.check_date,
chkdetail_t.amount,
chkdetail_t.vend_name,
chkdetail_t.chk_status,
chkdetail_t.reconsiled,
chkdetail_t.chk_type

check_number    chek_total
065757          50.00
065757          522.20
065757          581.70
065757          4492.88
065757          4832.92

我需要从上到下扫描check_number行并找到彼此相等的行，这样我就可以计算每个校验码的总和。

Answer 1

SELECT T.Check_Number, SUM(T.amount)
FROM chkdetail_t AS D
JOIN cheheader_t AS H
  ON H.check_acct = T.check_acct
GROUP BY T.check_Number