Question

我正在尝试使用jQuery datepicker仅在每年的7月和8月显示日期，除了8月31日之外它还有效。我也尝试过从7月中旬到9月中旬，它显示所有这些天除了无论如何，8月31日。

的jQuery

    function generateDates(){

        var availableDates = {};

        var startYear = (new Date()).getUTCFullYear();
        var endYear = 2050;

        for(var currentYear = startYear; currentYear <= endYear; currentYear++){

                //Loop over every year from current year to 2050
                for (var d = new Date(currentYear, 7, 1); d <= new Date(currentYear, 8, 31); d.setDate(d.getDate() + 1)) {

                    availableDates[d.getUTCFullYear() + "-0" + d.getUTCMonth() + "-" + (d.getUTCDate() <= 9 ? "0" + d.getUTCDate() : d.getUTCDate())] = 1;

                }

        }

        return availableDates;
}

$(function() {
var dates_allowed;



dates_allowed = generateDates();

$('#datepicker').datepicker({
    // these aren't necessary, but if you happen to know them, why not
    minDate: 0,
    maxDate: new Date(2050, 8, 31),

    // called for every date before it is displayed
    beforeShowDay: function(date) {

        // prepend values lower than 10 with 0
        function addZero(no) {
            if (no < 10){
              return "0" + no;
            }  else {
              return no; 
            }
        }

        var date_str = [
            addZero(date.getFullYear()),
            addZero(date.getMonth() + 1),
            addZero(date.getDate())      
        ].join('-');

        if (dates_allowed[date_str]) {
            return [true, 'good_date', 'This date is available'];
        } else {
            return [false, 'bad_date', 'We are sorry, this date is not available'];
        }
    }
});
});

HTML

<input id="datepicker" name="startdate" required>

非常感谢任何帮助。

此致

利

Answer 1

JavaScript的月份基于0，所以8月你想要：

new Date(2050, 7, 31)

当你将月份设置为8，那是9月，所以你试图说9月31日，这是不存在的。同样，你想调整7月的指数。

参考：https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Date

Answer 2

您可以使用getMonth检查当前日期的月份是7月和8月，而不是检查每个日期，或者使用getYear年份＆lt; = 2050。

Js日期对象引用：https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Date

代码：

 $(function () {

     $('#datepicker').datepicker({
         // these aren't necessary, but if you happen to know them, why not
         minDate: 0,
         maxDate: new Date(2050, 7, 31),

         // called for every date before it is displayed
         beforeShowDay: function (date) {

             if ((date.getMonth()==6 || date.getMonth()==7) && date.getYear()<=2050) {
                 return [true, 'good_date', 'This date is available'];
             } else {
                 return [false, 'bad_date', 'We are sorry, this date is not available'];
             }
         }
     });
 });

演示：http://jsfiddle.net/IrvinDominin/EQQrT/

datepicker（）不显示所有必需的日期

2 个答案: