Question

这已经被问了很多，但我找到的答案似乎没有用，所以我发帖在这里看看是否有人可以提供帮助。

我有这个

$sql = "SELECT SQL_CALC_FOUND_ROWS *, UNIX_TIMESTAMP(order_date) AS order_date, UNIX_TIMESTAMP(order_expected) AS order_expected
            FROM orders WHERE DATE(order_expected) BETWEEN NOW() AND DATE_ADD(NOW() - INTERVAL 7 DAY);

或

$sql = "SELECT SQL_CALC_FOUND_ROWS *, UNIX_TIMESTAMP(order_date) AS order_date, UNIX_TIMESTAMP(order_expected) AS order_expected
                FROM orders WHERE DATE(order_expected) BETWEEN NOW() AND DATE_ADD(NOW(), INTERVAL -7 DAY);

所有字段都名称正确，但似乎无法在今天之前的7天内获得其日期值。

请帮忙。

伊恩

Answer 1

试试这个： -

SELECT SQL_CALC_FOUND_ROWS *, UNIX_TIMESTAMP(order_date) AS order_date, UNIX_TIMESTAMP(order_expected) AS order_expected
FROM orders 
WHERE DATE(order_expected) BETWEEN DATE_ADD(NOW(), INTERVAL -7 DAY) AND NOW()

MYSQL今天之前的日期

1 个答案: