Question

我正在尝试使用java代码在android设备中编写和读取float数组（实际上相当大，640 * 480）。比如this one

    DataOutputStream out = ...;
for (int i=0; i<floatarray.length; ++i)
    out.writeFloat(floatarray[i]);

很慢，我已经尝试过了。

WRITE：

            float[] test=new float[3];
        test[0]=1.0f;
        test[1]=1.2f;
        test[2]=1.5f;
        //long timeBeforeWrite = System.nanoTime();
        try {
            BufferedOutputStream  dataOut = new BufferedOutputStream (
                    new FileOutputStream("/sdcard/DCIM/Camera/Dual/demo.bin"));

            byte buf[]=new byte[4*test.length];

            long timeBeforeWrite = System.nanoTime();

            for (int i=0; i<test.length; ++i)
            {
                int val = Float.floatToRawIntBits(test[i]);
                buf[4 * i] = (byte) (val >> 24);
                buf[4 * i + 1] = (byte) (val >> 16) ;
                buf[4 * i + 2] = (byte) (val >> 8);
                buf[4 * i + 3] = (byte) (val);
            }



            dataOut.write(buf);

            long ct_write = System.nanoTime();
            long offset_write = ct_write - timeBeforeWrite;
            float mOffsetInMs_write = (float)(offset_write)/1000000;
            Log.e("ETA", "write float[]  " + Float.toString(mOffsetInMs_write));

            dataOut.flush();
            dataOut.close();
        } catch (IOException ex) {
            System.err.println(ex.getMessage());
        }

READ：

            float[] read=new float[3];

        try{
            BufferedInputStream  dataIn=new BufferedInputStream (new FileInputStream("/sdcard/DCIM/Camera/Dual/demo.txt"));
            byte buf[]=new byte[4*read.length];
            long timeBeforeWrite = System.nanoTime();

            dataIn.read(buf);

            for (int i=0; i<read.length; ++i)
            {
                    int val;
val = buf[4 * i] << 24;
                    val += buf[4 * i + 1] << 16;
                    val += buf[4 * i + 2] << 8;
                    val += buf[4 * i + 3];

                read[i]=Float.valueOf(Integer.toBinaryString(val));

                //int val = Float.floatToRawIntBits(disparityMap[i]);

            }

            long ct_write = System.nanoTime();
            long offset_write = ct_write - timeBeforeWrite;
            float mOffsetInMs_write = (float)(offset_write)/1000000;
            Log.e("ETA", "read float[]  " + Float.toString(mOffsetInMs_write));

            dataIn.close();

        }catch (IOException ex) {
            System.err.println(ex.getMessage());
        }

回读的东西是非常奇怪的浮点值，这有什么问题？顺便说一下，回读运行得很慢，不知道为什么。或者快速读/写浮点数组的任何其他好主意？

谢谢！

//感谢Larry，我尝试了一下bytebuffer.asfloatbuffer（）方式：

//WRITE
    float[] test = new float[3];
    test[0]=1.1f;
    test[1]=1.2f;
    test[2]=1.5f;
    try{
        RandomAccessFile aFile = new RandomAccessFile("/sdcard/demo.data", "rw");
        FileChannel outChannel = aFile.getChannel();

        //one float 3 bytes
        ByteBuffer buf = ByteBuffer.allocate(12);
        buf.clear();
        buf.asFloatBuffer().put(test);

        //while(buf.hasRemaining()) 
        {
            outChannel.write(buf);
        }

        outChannel.close();

    }
    catch (IOException ex) {
        System.err.println(ex.getMessage());
    }

    //READ
    float[] readback=new float[3];
    try{


        RandomAccessFile rFile = new RandomAccessFile("/sdcard/demo.data", "rw");
        FileChannel inChannel = rFile.getChannel();
        ByteBuffer buf_in = ByteBuffer.allocate(12);
        buf_in.clear();

        inChannel.read(buf_in);

        buf_in.asFloatBuffer().get(readback);

        inChannel.close();

    }
    catch (IOException ex) {
        System.err.println(ex.getMessage());
    }

并且程序在buf_in.asFloatBuffer().get(readback);中崩溃任何想法，有没有方法进入和调试内部java，抱歉全新的java世界。再次感谢

Answer 1

感谢Larry，我只是在分享我的代码，希望它可以帮助其他人。

我只想弄清楚，我们需要在读/写文件通道后回放到缓冲区。以下代码正常运行，运行速度非常快。

float[] disparity=new float[640*480];

    disparity[1]=1.5f;
    disparity[2]=4.566f;

//WRITE
    try{
        RandomAccessFile aFile = new RandomAccessFile("/sdcard/demo.data", "rw");
        FileChannel outChannel = aFile.getChannel();

        //one float 4 bytes
        ByteBuffer buf = ByteBuffer.allocate(4*640*480);
        buf.clear();
        buf.asFloatBuffer().put(disparity);

        //while(buf.hasRemaining()) 
        {
            outChannel.write(buf);
        }

        //outChannel.close();
        buf.rewind();

        float[] out=new float[3];
        buf.asFloatBuffer().get(out);

        outChannel.close();

    }
    catch (IOException ex) {
        System.err.println(ex.getMessage());
    }

    //READ
    float[] readback=new float[640*480];
    try{

        RandomAccessFile rFile = new RandomAccessFile("/sdcard/demo.data", "rw");
        FileChannel inChannel = rFile.getChannel();
        ByteBuffer buf_in = ByteBuffer.allocate(640*480*4);
        buf_in.clear();

        inChannel.read(buf_in);

        buf_in.rewind();
        buf_in.asFloatBuffer().get(readback);

        inChannel.close();

    }
    catch (IOException ex) {
        System.err.println(ex.getMessage());
    }

再次感谢。

Answer 2

尝试使用FileChannel进行文件访问，使用ByteBuffer进行数据访问。您可以使用ByteBuffer方法将数据放入ByteBuffer.putFloat()，并使用FileChannel.write()将其写出来。当您回读它时，您可以调用FileChannel.read()来获取表示数据的ByteBuffer，然后调用ByteBuffer.asFloatBuffer()以获得表示数据的FloatBuffer，然后可以使用该float[]来获取{{1}} 1}}。

Answer 3

只需在DataOutputStream和FileOutputStream之间添加一个BufferedOutputStream。

用java快速写入/读取float数组

3 个答案: