Question

ArrayList<HashMap<String, ?>>  list;
f(!list.isEmpty()){

          adapter = new MySimpleArrayAdapter(getActivity(),R.layout.inner_base_header_cutom, list);
          listview.setAdapter(adapter);
          Log.i("LIST Active", "LIST Active" + list.size());
      }

public class MySimpleArrayAdapter extends ArrayAdapter<ArrayList<HashMap<String, ?>>> {
          private final Context context;
          private final ArrayList<HashMap<String, ?>> values;

          public MySimpleArrayAdapter(Context context, int innerBaseHeaderCutom, ArrayList<HashMap<String, ?>> list) {
            super(context, innerBaseHeaderCutom, list);
            this.context = context;
            this.values = list;
          }

}

ERROR：

The constructor ArrayAdapter<ArrayList<HashMap<String,?>>>(Context, int, ArrayList<HashMap<String,?>>) is undefined

也无法删除ListView：

remove(list.get(position));

错误：

The method remove(ArrayList<HashMap<String,?>>) in the type ArrayAdapter<ArrayList<HashMap<String,?>>> is not applicable for the arguments (HashMap<String,capture#2-of ?>)

Answer 1

当你调用超类

的构造函数时，只需删除最后一个参数

super(context, innerBaseHeaderCutom);

编辑：
另一个人认为你可以尝试改变这个：

public class MySimpleArrayAdapter extends ArrayAdapter<ArrayList<HashMap<String, ?>>> {

代表

public class MySimpleArrayAdapter extends ArrayAdapter<HashMap<String, ?>> {

在构造函数中进行相同的更改。

Answer 2

You are creating ArrayList with ArrayList<HashMap<String, ?>> instead you can try ArrayList<HashMap<String, ? extends Object>>

检查示例代码和输出。

public class MyJavaTesting{
public MyJavaTesting(ArrayList<HashMap<String, ? extends Object>> list) {
    System.out.println(list);
}

public static void main(String[] args) {
    ArrayList<HashMap<String, ? extends Object>> list = new ArrayList<HashMap<String,?>>();
    HashMap<String, String> map1 = new HashMap<String, String>();
    map1.put("Key", "value");
    list.add(map1);

    HashMap<String, Object> map2 = new HashMap<String, Object>();
    map2.put("Key", new Object());
    list.add(map2);

    MyJavaTesting manager = new MyJavaTesting(list);
}
}

<强>输出： [{Key = value}，{Key = java.lang.Object @ 4f1d0d}]

无法使用ArrayList <hashmap <string，？>＆gt;＆gt; </hashmap <string，？>填充listView

2 个答案: