Question

这段代码有什么问题？（我试图让用户输入10个整数，然后返回最大的奇数，如果没有赔率则返回一个声明如此说明）

numbers = raw_input('Enter 10 integers separated by comma ')
numbers = [numbers.split(',')]
odds = [x for x in numbers if x%2==1]

if not odds:
 print "no odd number was entered"
else:
 print max(odds)

Answer 1

我猜numbers是str个实例的列表。试试numbers = [int(n) for n in numbers.split(',')]。

Answer 2

你需要做两件事：

删除此行上的方括号：
```
numbers = [numbers.split(',')]
```
否则，str.split返回的列表将放在另一个列表中。

将str.split返回的字符串列表转换为整数列表。这可以通过map和int完成：

numbers = map(int, numbers.split(','))

否则，下一行中的%将被解释为字符串格式，这将引发错误：

Traceback (most recent call last):
  File ".\t.py", line 3, in <module>
    odds = [x for x in numbers if x%2==1]
TypeError: not all arguments converted during string formatting

以下是您脚本的固定版本：

numbers = raw_input('Enter 10 integers separated by comma ')
numbers = map(int, numbers.split(','))
odds = [x for x in numbers if x%2==1]

# The Python standard for indentation is 4 spaces
if not odds:
    print "no odd number was entered"
else:
    print max(odds)

演示：

>>> numbers = raw_input('Enter 10 integers separated by comma ')
Enter 10 integers separated by comma 1,2,3,4,5,6,7,8,9,10
>>> numbers = map(int, numbers.split(','))
>>> odds = [x for x in numbers if x%2==1]
>>> if not odds:
...     print "no odd number was entered"
... else:
...     print max(odds)
...
9
>>>

如何在python中获取列表中每个数字的mod

2 个答案: