Question

尝试从此列表中删除\ u0141，我尝试将其插入到我的数据库中

results=[['The Squid Legion', '0', u'Banda \u0141ysego', '1', ["\nRazer's Clash of the Gods EU #12 - \nChallonge\n"]], ['Romanian eSports', '1', 'Love', '0', ["\nRazer's Clash of the Gods EU #12 - \nChallonge\n"]]]

results =[[x.encode('ascii', 'ignore')  for x in l] for l in results]

我收到此错误：

AttributeError: 'list' object has no attribute 'encode'

Answer 1

“大列表”中的第一个列表包含一个列表["\nRazer's Clash of the Gods EU #12 - \nChallonge\n"]，它显然没有encode()方法。

所以你的算法会发生什么：

[[somestring.encode, somestring.encode, somestring.encode, [somestring].encode, ...]

您可以使用简单的递归算法：

def recursive_ascii_encode(lst):
    ret = []
    for x in lst:
        if isinstance(x, basestring):  # covers both str and unicode
            ret.append(x.encode('ascii', 'ignore'))
        else:
            ret.append(recursive_ascii_encode(x))
    return ret

print recursive_ascii_encode(results)

输出：

[['The Squid Legion', '0', 'Banda ysego', '1', ["\nRazer's Clash of the Gods EU #12 - \nChallonge\n"]], ['Romanian eSports', '1', 'Love', '0', ["\nRazer's Clash of the Gods EU #12 - \nChallonge\n"]]]

当然，这实际上是一个更通用的递归映射的特例，重构的，如下所示：

def recursive_map(lst, fn):
    return [recursive_map(x, fn) if isinstance(x, list) else fn(x) for x in lst]

print recursive_map(results, lambda x: x.encode('ascii', 'ignore'))

Python编码列表'list'对象没有属性'encode'

1 个答案: