Question

data,   ID, Value,  Exp1

201101, 1,  2   
201202, 1,  3   
201303, 1,  4   
201101, 2,  2   
201202, 2,  3   
201303, 2,  4   
201304, 2,  5   
201305, 2,  6   
201306, 2,  7   
201307, 2,  8   
201308, 2,  9   
201309, 2,  10  
201310, 2,  11  
201311, 2,  12  
201312, 2,  13

我必须将Exp1的值计算为

代表ID=2。 Exp1= (sum of value from 201307 to 201312)/6-(sum of value from 201301 to 201306)/6

有些ID可能没有所有月份的值，有些可能只有一个值。

这可能在SQL吗？

ID为2的

：Exp1 =（13 + 12 + 11 + 10 + 9 + 8）/ 6-（7 + 6 + 5 + 4 + 3 + 2）/ 6

表示ID 1：Exp1 =（0 + 0 + 0 + 0 + 0 + 0 + 0 + 0）/ 6-（2 + 3 + 4 + 0 + 0 + 0）/ 6

必须为所有IDS

完成此操作

Answer 1

select 
ID,
sum(
    case 
      when YRMO between 201307 and 201312 then value 
      else 0 
    end)/6 
- sum(
    case 
      when YRMO between 201301 and 201306 then value 
      else 0 
    end)/6 as EXP1

from TABLE
group by ID;

Answer 2

select 
  id, 
  sum(value) / 6 exp1
from (
  select 
    id, 
    case when YRMO between '201301' and '201306' then -value else value end value
  from `table`
  where YRMO between '201301' and '201312' 

) q
group by id

SQL复杂求和

2 个答案: