Question

我有一个随机数组，我必须搜索整数在数组中的次数。这就是我已经拥有的。你会如何搜索结果数组？

Console.WriteLine("enter number:");

int number = Convert.ToInt32(Console.ReadLine());
int[] array = new int[number];
Random rnd = new Random();

for ( int i = 0; i < array.Length; i++)
{
    array[i] = rnd.Next(0 , number);
}

foreach (int i in array)
{
    System.Console.Write(" {0}",i);
}

Console.ReadKey();

Answer 1

foreach(var g in array.GroupBy(x=>x))
{
    Console.WriteLine("{0} Count:{1}",g.Key,g.Count())
}

Answer 2

其他答案依赖于LINQ，这是使用普通C＃

执行此操作的代码

int count = 0;

foreach (int i in array)
{
    if (i == number)
        count = count + 1;
}

请注意，在现有代码中，这将始终生成0，因为Random.Next()的上限是独占的。您应该将代码更改为此类型，其中输入的数字未链接到您生成的数组：

int array_size = 1000;
int max_number = 100;
int[] array = new int[array_size];
Random rnd = new Random();

for (int i = 0; i < array.Length; i++)
    array[i] = rnd.Next(0, max_number);

Console.WriteLine("enter number:");
int number = Convert.ToInt32(Console.ReadLine());

foreach (int i in array)
    System.Console.Write("{0} ", i);

int count = 0;
foreach (int i in array)
    if (i == number)
        count = count + 1;

Console.WriteLine("Number {0} was found {1} times in the array", number, count);

Console.ReadKey();

C＃搜索数组

2 个答案: