Question

我已将SQL查询的结果加载到数组中。字段为ComputerName，time_in_days，room，键入ComputerName。

我想了解每个time_in_days发生的次数。

数组的示例值为：

[STU-CZC1087SNC] => Array
    (
        [ComputerName] => STU-CZC1087SNC
        [time_in_days] => 0
        [room] => 4Q08
    )

[STU-CZC02501QT] => Array
    (
        [ComputerName] => STU-CZC02501QT
        [time_in_days] => 12
        [room] => 2R017
    )

所以我想知道有多少台计算机有time_in_days = 12，有多少计算机有time_in_days = 0。

它将用于绘制图表。

我该怎么做/最好的方法是什么？

Answer 1

$result = count(
    array_filter(
        $myArray,
        function($value) {
            return $value['time_in_days'] == 12;
        }
    )
);

Answer 2

试试这个，其中$ input是包含计算机数据的数组数组：

$result = array();
foreach($input as $computerName => $arr){
  if(!isset($result[ $arr['time_in_days'] ]))
    $result[ $arr['time_in_days'] ] = 0;
  $result[ $arr['time_in_days'] ]++;
}
return $result;

结果如下：

[
  12 => 2, //2 computers have time_in_days of 12
  0 => 1  //1 computer has time_in_days of 0
]

Answer 3

好的，这是工作示例：

<?php

$computerarray = [
'STU-CZC1087SNC' => Array
(
    'ComputerName' => 'STU-CZC1087SNC',
    'time_in_days' => 0,
    'room' => '4Q08'
),

'STU-CZC02501QT' => Array
(
    'ComputerName' => 'STU-CZC02501QT',
    'time_in_days' => 12,
    'room' => '2R017'
),
'STU-CZC02501QF' => Array
(
    'ComputerName' => 'STU-CZC02501QT',
    'time_in_days' => 12,
    'room' => '2R017'
)    
];


$myarray = array();
foreach($computerarray as $key => $val){
    $myarray[] = $val['time_in_days'];
}

echo "<pre>";
$myarray = array_count_values($myarray);
print_r($myarray);

Answer 4

这应该有效 -

$my_arr = Array();
array_walk($arr, function($v) use(&$my_arr) {$my_arr[] = $v['time_in_days'];});
$time_freq = array_count_values($my_arr);
var_dump($time_freq);
/**
  OUTPUT
**/
array
  0 => int 1
  12 => int 2

Answer 5

我删除了对以下问题的评论：

执行此操作的最佳方法是不使用php，而是使用sql month GROUP BY并调用time_in_days。这是the right direction的推动。

对于无条件的功能方法，这里使用专门为此任务设计的两个函数：array_count_values()和array_column()

代码：（Demo）

COUNT()

输出：

$computerarray = [
    'STU-CZC1087SNC' => ['ComputerName' => 'STU-CZC1087SNC','time_in_days' => 0,'room' => '4Q08'],
    'STU-CZC02501QT' => ['ComputerName' => 'STU-CZC02501QT','time_in_days' => 12,'room' => '2R017'],
    'STU-CZC02501QF' => ['ComputerName' => 'STU-CZC02501QT','time_in_days' => 12,'room' => '2R017']    
];

var_export(array_count_values(array_column($computerarray,'time_in_days')));

Answer 6

也许是array_count_values，参见手册： http://pl1.php.net/array_count_values

Answer 7

foreach($ya as $a) {
    $newarr[$a['time_in_days']]++;
}

Answer 8

$total = null; 
foreach ($members as $owner): 
    if($owner['circle_id'] == $c['id']): // or if($owner['circle_id'] == 1):
        $total = $total + 1;
    endif;
endforeach;
echo $total;

此代码计算圆圈内的成员数。它将成员Table id与当前圈号id匹配。其当前值为$c['id'] = 1

计算PHP数组中值的出现次数

8 个答案: