Question

以下代码：

$services = $this->find('all', array(
            'contain' => array('Category','Country'),
            'joins' => array(
                 array('table' => 'services_to_categories',
                    'alias' => 'ServiceCategory',
                    'type' => 'INNER',
                    'conditions' => array(
                        'ServiceCategory.service_id = Service.id'
                    )
                )
            ),
            'group' => 'Service.id'
        ));
        return $services;

给我输出结果：

我需要输出如下所示：

Accounting & Financial
job_title: director 

Awards & Incentives
job_title: director

Data Management
job_title: director 
job_title: d
job_title: e

Internet Services
job_title: d

Business Consulting
job_title: e

如何在上面的输出中使用这个数组变量$ services？

Answer 1

基本上，我所做的只是遍历数组并创建一个新类别，其中类别为键，作业标题为值数组。然后我只是通过我的新阵列循环并吐出关键和值。

<?php

$category_array = array();


// LOOP THROUGH THE MAIN ARRAY AND RESTRUCTURE IT
foreach ($start_array AS $array_element) {
    foreach ($array_element['Category'] AS $category) {
        $category_array[$category['category']][] = $array_element['Service']['job_title'];
    }
}


// LOOP THROUGH OUR NEW ARRAY AND PRINT OUT THE KEY AND VALUES
foreach ($category_array AS $department => $job_title_array) {
    print $department;
    foreach ($job_title_array AS $job_title) {
        print "\njob_title: ".$job_title;
    }
    print "\n\n";
}

Here is a working demo

Answer 2

您无法使用查询解决此问题。

你想要的是这样的：

+------------------------+----------+
| Accounting & Financial | director |
+------------------------+----------+
| Data Management        | director |
|                        +----------+
|                        | d        |
|                        +----------+
|                        | e        |
+------------------------+----------+

显然，SQL适用于表，而不是嵌套树，因此无法完成。

1）SQL会给你（使用GROUP BY Service.job_title）：

+------------------------+----------+
| Accounting & Financial | director |
+------------------------+----------+
| Data Management        | d        |
+------------------------+----------+
| Data Management        | e        |
+------------------------+----------+

2）或者这个（使用GROUP BY Category.category）：

+------------------------+----------+
| Accounting & Financial | director |
+------------------------+----------+
| Data Management        | director |
+------------------------+----------+

3）或者这个（不使用GROUP BY）：

+------------------------+----------+
| Accounting & Financial | director |
+------------------------+----------+
| Data Management        | director |
+------------------------+----------+
| Data Management        | d        |
+------------------------+----------+
| Data Management        | e        |
+------------------------+----------+

如果您丢失了数据：Data Management | director不再出现在结果中。

在案例2中，您也会丢失数据：Data Management | d和Data Management | e不再出现在结果中。

所以你必须使用案例3.然后手动（在代码中）将此结果转换为您想要的嵌套数组。

PS：这些是伪结果。实际结果取决于与数据库有关的各种因素。

在类别中显示职位，但同一类别不要重复

2 个答案: