合并多个点旋风

时间:2014-03-06 09:22:40

标签: c# winforms zedgraph

我有一个.wav文件,我正在使用ZedGraph绘制波形。我正在计算每秒的.wav文件的能量,如果能量小于4,我想用不同的颜色绘制样本。我创建了两个PointPairLlistLineItem来执行此操作,但在合并这两个列表时出现问题。这是我的代码以及我的图表的显示方式。

LineItem myCurveAudio;
LineItem myCurveAudio2;
PointPairList list1 = new PointPairList();
PointPairList list2 = new PointPairList();
while(true)
{
for (int i = 0; i < fmainBuffer.Length; i++)
{
   float segmentSquare = fmainBuffer[i] * fmainBuffer[i];
   listOfSquaredSegment.Add(segmentSquare);
}
float energy = (float)Math.Sqrt(listOfSquaredSegment.Sum());
if (energy < 4)
{
    for (int i = 0; i < read; i += (int)window)
    {
       list1.Add((float)(count / ((float)read / (float)window)), fmainBuffer[i]);
       count++;
    }
}
else
{
   for (int i = 0; i < read; i += (int)window)
   {
       list4.Add((float)(count / ((float)read / (float)window)), fmainBuffer[i]);
       count++;
   }
}
}
zgc.MasterPane.PaneList[1].XAxis.Scale.MaxAuto = true;
zgc.MasterPane.PaneList[1].XAxis.Scale.MinAuto = true;
zgc.MasterPane.PaneList[1].XAxis.Type = AxisType.Linear;
zgc.MasterPane.PaneList[1].XAxis.Scale.Format = "";
zgc.MasterPane.PaneList[1].XAxis.Scale.Min = 0;
myCurveAudio = zgc.MasterPane.PaneList[1].AddCurve(null, list1, Color.Lime, SymbolType.None);
myCurveAudio2 = zgc.MasterPane.PaneList[1].AddCurve(null, list4, Color.Red, SymbolType.None);

enter image description here myCurveAudio和myCurveAudio2的线条如图所示相交。

如何合并这两个列表以防止这些交叉点?

我还尝试将`double.NaN添加到列表的末尾,但它不起作用。

2 个答案:

答案 0 :(得分:0)

尝试以下代码,我根据“this thread

修改了代码
LineItem myCurveAudio;
LineItem myCurveAudio2;
PointPairList list1 = new PointPairList();
PointPairList list2 = new PointPairList();
double lastAddedHighEnergy = double.NaN;
double lastAddedLowEnergy = double.NaN;
while (true)
{
    for (int i = 0; i < fmainBuffer.Length; i++)
    {
        float segmentSquare = fmainBuffer[i] * fmainBuffer[i];
        listOfSquaredSegment.Add(segmentSquare);
    }
    float energy = (float)Math.Sqrt(listOfSquaredSegment.Sum());
    if (energy < 4)
    {
        for (int i = 0; i < read; i += (int)window)
        {
            lastAddedLowEnergy = (double)(count / ((double)read / (double)window));
            if (lastAddedHighEnergy != double.NaN)
            {
                list1.Add(lastAddedHighEnergy + ((lastAddedLowEnergy - lastAddedHighEnergy) / 2.0), double.NaN);
                lastAddedHighEnergy = double.NaN;
            }

            list1.Add(lastAddedLowEnergy, fmainBuffer[i]);
            count++;
        }
    }
    else
    {
        for (int i = 0; i < read; i += (int)window)
        {
            lastAddedHighEnergy = (double)(count / ((double)read / (double)window));
            if (lastAddedLowEnergy != double.NaN)
            {
                list2.Add(lastAddedLowEnergy + ((lastAddedHighEnergy - lastAddedLowEnergy) / 2.0), double.NaN);
                lastAddedLowEnergy = double.NaN;
            }

            list2.Add(lastAddedHighEnergy, fmainBuffer[i]);
            count++;
        }
    }
}

zgc.MasterPane.PaneList[1].XAxis.Scale.MaxAuto = true;
zgc.MasterPane.PaneList[1].XAxis.Scale.MinAuto = true;
zgc.MasterPane.PaneList[1].XAxis.Type = AxisType.Linear;
zgc.MasterPane.PaneList[1].XAxis.Scale.Format = "";
zgc.MasterPane.PaneList[1].XAxis.Scale.Min = 0;
myCurveAudio = zgc.MasterPane.PaneList[1].AddCurve(null, list1, Color.Lime, SymbolType.None);
myCurveAudio2 = zgc.MasterPane.PaneList[1].AddCurve(null, list2, Color.Red, SymbolType.None);

如果上述代码无效,请按照this thread

中给出的步骤操作

答案 1 :(得分:0)

Gradient Fills to Color Line Segments

本教程帮助我解决了我的问题。不需要两个或更多PointPairList这是我的代码:

float energy = (float)Math.Sqrt(listOfSquaredSegment.Sum());
for (int i = 0; i < fmainBuffer.Length; i += (int)window)
{
     listaudio.Add((float)(count / ((float)8000 / (float)window)) / 5, fmainBuffer[i], energy > 4 ? 2.0 : 1.0);
     count++;
}
myCurveAudio = zgc.MasterPane.PaneList[1].AddCurve(null, listaudio, Color.Lime, SymbolType.None);
Fill fill = new Fill(Color.Lime, Color.Red);
fill.RangeMin = 1;
fill.RangeMax = 2;
fill.Type = FillType.GradientByZ;
myCurveAudio.Line.GradientFill = fill;