我正在尝试在2列的GridLayout中显示标签。我似乎无法显示文本和下面的水平线:
public void foo(){
popupShell = new Shell(Display.getDefault(), SWT.NO_TRIM | SWT.ON_TOP | SWT.MODELESS);
//popupShell.setLayoutData(new GridData(GridData.FILL_HORIZONTAL));
popupShell.setLayout(createNoMarginLayout(2, false));
Label history = new Label(popupShell, SWT.SEPARATOR | SWT.SHADOW_OUT | SWT.HORIZONTAL);
history.setText("History");
history.setVisible(true);
Label fill = new Label(popupShell, SWT.NONE);
fill.setSize(0,30);
}
public static GridLayout createNoMarginLayout(int numColumns, boolean makeColumnsEqualWidth) {
GridLayout layout = new GridLayout(numColumns, makeColumnsEqualWidth);
layout.verticalSpacing = 0;
layout.horizontalSpacing = 0;
layout.marginTop = 0;
layout.marginBottom = 0;
layout.marginLeft = 0;
layout.marginRight = 0;
layout.marginWidth = 0;
layout.marginHeight = 0;
return layout;
}
我得到的只是没有文字的那一行。
我做错了什么?
答案 0 :(得分:1)
Label
样式的SWT.SEPARATOR
不会显示任何文字值。您必须使用单独的控件来显示文本。
来自Label
来源,显示setText
完全忽略了SWT.SEPARATOR
:
public void setText (String string) {
checkWidget();
if (string == null) error (SWT.ERROR_NULL_ARGUMENT);
if ((style & SWT.SEPARATOR) != 0) return;
...