std :: length_error在内存位置0x002ff5dc处的未处理异常

时间:2014-03-06 07:17:25

标签: c++ opencv unhandled-exception wavelet

我是opencv中的新手 这是我的代码

 #include <opencv2/imgproc/imgproc.hpp>
    #include <opencv2/highgui/highgui.hpp>

#include <iostream> 
#include <fstream>
#include <vector>
#include <string>
#include <complex>
#include <cmath>
#include <algorithm>
#include "wavelet2d.h"
#include "opencv/cv.h"
#include "opencv/highgui.h"
#include "opencv/cxcore.h"

using namespace std;
using namespace cv;

void* maxval(vector<vector<double> > &arr, double &max){
    max = 0;
    for (unsigned int i =0; i < arr.size(); i++) {
        for (unsigned int j =0; j < arr[0].size(); j++) {
            if (max <= arr[i][j]){
                max = arr[i][j];
            }
        }
    }
    return 0;
}

void* maxval1(vector<double> &arr, double &max){
    max = 0;
    for (unsigned int i =0; i < arr.size(); i++) {
        if (max <= arr[i]){
            max = arr[i];
        }

    }
    return 0;
}


int main() {
    IplImage* img = cvLoadImage("apple.jpg");
    if (!img){
        cout << " Can't read Image. Try Different Format." << endl;
        exit(1);
    }
    int height, width;
    height = img->height;
    width = img->width;
    int nc = img->nChannels;
    //   uchar* ptr2 =(uchar*) img->imageData;
    int pix_depth = img->depth;
    CvSize size;
    size.width =width;
    size.height=height;
    cout << "depth" << pix_depth <<  "Channels" << nc << endl;


    cvNamedWindow("Original Image", CV_WINDOW_AUTOSIZE);
    cvShowImage("Original Image", img);
    cvWaitKey();
    cvDestroyWindow("Original Image");
    cvSaveImage("orig.bmp",img);


    int rows =(int) height;
    int cols =(int) width;
    Mat matimg(img);

    vector<vector<double> > vec1(rows, vector<double>(cols));


    int k =1;
    for (int i=0; i < rows; i++) {
        for (int j =0; j < cols; j++){
            unsigned char temp;
            temp = ((uchar*) matimg.data + i * matimg.step)[j  * matimg.elemSize() + k ];
            vec1[i][j] = (double) temp;
        }

    }

    string nm = "db3";
    vector<double> l1,h1,l2,h2;
    filtcoef(nm,l1,h1,l2,h2);
    // unsigned int lf=l1.size();
    //  int rows_n =(int) (rows+ J*(lf-1));
    //  int cols_n =(int)  (cols + J * ( lf -1));

    // Finding 2D DWT Transform of the image using symetric extension algorithm
    // Extension is set to 3 (eg., int e = 3)

    vector<int> length;
    vector<double> output,flag;
    int J =3;
    dwt_2d_sym(vec1,J,nm,output,flag,length);

    double max;
    vector<int> length2;
    // This algorithm computes DWT of image of any given size. Together with convolution and
    // subsampling operations it is clear that subsampled images are of different length than
    // dyadic length images. In order to compute the "effective" size of DWT we do additional
    // calculations.
    dwt_output_dim_sym(length,length2,J);
    // length2 is gives the integer vector that contains the size of subimages that will
    // combine to form the displayed output image. The last two entries of length2 gives the
    // size of DWT ( rows_n by cols_n)

    int siz = length2.size();
    int rows_n=length2[siz-2];
    int cols_n = length2[siz-1];

    vector<vector< double> > dwtdisp(rows_n, vector<double>(cols_n));
    dispDWT(output,dwtdisp, length ,length2, J);

    // dispDWT returns the 2D object dwtdisp which will be displayed using OPENCV's image
    // handling functions

    vector<vector<double> >  dwt_output= dwtdisp;

    maxval(dwt_output,max);// max value is needed to take care of overflow which happens because
    // of convolution operations performed on unsigned 8 bit images

    //Displaying Scaled Image
    // Creating Image in OPENCV
    IplImage *cvImg; // image used for output
    CvSize imgSize; // size of output image

    imgSize.width = cols_n;
    imgSize.height = rows_n;

    cvImg = cvCreateImage( imgSize, 8, 1 );
    // dwt_hold is created to hold the dwt output as further operations need to be
    // carried out on dwt_output in order to display scaled images.
    vector<vector<double> > dwt_hold(rows_n, vector<double>( cols_n));
    dwt_hold = dwt_output;
    // Setting coefficients of created image to the scaled DWT output values
    for (int i = 0; i < imgSize.height; i++ ) {
        for (int j = 0; j < imgSize.width; j++ ){
            if ( dwt_output[i][j] <= 0.0){
                dwt_output[i][j] = 0.0;
            }
            if ( i <= (length2[0]) && j <= (length2[1]) ) {
                ((uchar*)(cvImg->imageData + cvImg->widthStep*i))[j] =
                        (char) ( (dwt_output[i][j] / max) * 255.0);
            } else {
                ((uchar*)(cvImg->imageData + cvImg->widthStep*i))[j] =
                        (char) (dwt_output[i][j]) ;
            }
        }
    }

    cvNamedWindow( "DWT Image", 1 ); // creation of a visualisation window
    cvShowImage( "DWT Image", cvImg ); // image visualisation
    cvWaitKey();
    cvDestroyWindow("DWT Image");
    cvSaveImage("dwt.bmp",cvImg);

    // Finding IDWT

    vector<vector<double> > idwt_output(rows, vector<double>(cols));

    idwt_2d_sym(output,flag, nm, idwt_output,length);



    //Displaying Reconstructed Image

    IplImage *dvImg;
    CvSize dvSize; // size of output image

    dvSize.width = idwt_output[0].size();
    dvSize.height = idwt_output.size();

    cout << idwt_output.size() << idwt_output[0].size() << endl;
    dvImg = cvCreateImage( dvSize, 8, 1 );

    for (int i = 0; i < dvSize.height; i++ )
        for (int j = 0; j < dvSize.width; j++ )
            ((uchar*)(dvImg->imageData + dvImg->widthStep*i))[j] =
                    (char) (idwt_output[i][j])  ;

    cvNamedWindow( "Reconstructed Image", 1 ); // creation of a visualisation window
    cvShowImage( "Reconstructed Image", dvImg ); // image visualisation
    cvWaitKey();
    cvDestroyWindow("Reconstructed Image");
    cvSaveImage("recon.bmp",dvImg);







    return 0;
}

当我编译输出成功时,可以显示苹果的图像

但是当我想通过按Enter来小写这个图像时,它崩溃了,这里它说: lab09.exe中0x7736c41f处的未处理异常:Microsoft C ++异常:内存位置0x003bf30c处的std :: length_error ..中断或者继续

请帮助我谢谢。

0 个答案:

没有答案
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