Question

我想从输入字符串中过滤掉srcport和dstport。这是我试过的代码：

String input = "2014<>10.100.2.3<><189>date=2014-01-16,time=11:26:14,devname=B3909601569,devid=B3909601569,logid=000013,type=traffic,srcip=192.168.192.123,srcport=2072,srcintf=port2,dstip=10.180.1.105,dstport=3206,dstintf=port1,sessionid=121543,status=close,policyid=196,service=MYSQL,proto=6,duration=10,sentbyte=3910,rcvdbyte=175085,sentpkt=74,rcvdpkt=132";

Pattern p = Pattern.compile("(srcport=)(\\d+).[\\s]?(dstport=)(\\d+)");
Matcher m = p.matcher(input);

StringBuffer result=new StringBuffer();

while (m.find()) {

System.out.println("Srcport: " + m.group(2) + " & ");
System.out.println("Dstport: " + m.group(4));

}

System.out.println(result);

但它没有显示任何输出。正则表达式中是否存在错误

Pattern p = Pattern.compile("(srcport=)(\\d+).[\\s]?(dstport=)(\\d+)");

或println行

System.out.println("Srcport: " + m.group(2) + " & ");
System.out.println("Dstport: " + m.group(4));"

任何建议都将受到高度赞赏。

Answer 1

请参阅以下对正则表达式和捕获的组的更改：

    String input = "2014<>10.100.2.3<><189>date=2014-01-16,time=11:26:14,devname=B3909601569,devid=B3909601569,logid=000013,type=traffic,srcip=192.168.192.123,srcport=2072,srcintf=port2,dstip=10.180.1.105,dstport=3206,dstintf=port1,sessionid=121543,status=close,policyid=196,service=MYSQL,proto=6,duration=10,sentbyte=3910,rcvdbyte=175085,sentpkt=74,rcvdpkt=132";
    Pattern p = Pattern.compile("srcport=(\\d+).*?dstport=(\\d+)"); // update regex
    Matcher m = p.matcher(input);

    StringBuffer result=new StringBuffer();

    while (m.find()) {

        System.out.println("Srcport: " + m.group(1)); //print groups 1 + 2
        System.out.println("Dstport: " + m.group(2));

    }

    System.out.println(result);

Answer 2

您忘记在正则表达式中使用或（|）

srcport=(\\d+)|dstport=(\\d+)

您的代码将是

while (m.find()) 
{
    if(m.group().startsWith("srcport"))
        System.out.println("Srcport: " + m.group(1) + " & ");
    else
        System.out.println("Dstport: " + m.group(1));

}

Answer 3

试试这个：

Pattern p = Pattern.compile("srcport=(\\d+)|dstport=(\\d+)");

Answer 4

尝试以下代码。我在我的系统中运行它并且它工作正常。

String input =“2014＆lt;＆gt; 10.100.2.3＆lt;＆gt;＆lt; 189＆gt; date = 2014-01-16，time = 11：26：14，devname = B3909601569，devid = B3909601569，logid = 000013，类型=流量，srcip = 192.168.192.123，srcport = 2072，srcintf = PORT2，dstip = 10.180.1.105，dstport = 3206，目的接口= PORT1，的sessionid = 121543，状态=关闭，策略ID = 196，服务= MYSQL，原= 6，持续时间= 10，sentbyte = 3910，rcvdbyte = 175085，sentpkt = 74，rcvdpkt = 132" ;

    Pattern p = Pattern.compile("(srcport=)(\\d+)((.*)?)(dstport=)(\\d+)(\\.)*");
    Matcher m = p.matcher(input);

    StringBuffer result=new StringBuffer();

    while (m.find()) {
        System.out.println(m.group());
        System.out.println("Srcport: " + m.group(2) );
        System.out.println("Dstport: " + m.group(6));

    }

如何有效地过滤掉一些带有正则表达式的子串？

4 个答案: