Question

我正在尝试使用query命令获取每个类的值。下面是我得到的示例UI组件：

[0] {
          "class" => "UITabBarSwappableImageView",
             "id" => "imageView-34",
           "rect" => {
        "center_x" => 288,
               "y" => 522,
           "width" => 48,
               "x" => 264,
        "center_y" => 538,
          "height" => 32
    },
          "frame" => {
             "y" => 2,
         "width" => 48,
             "x" => 6,
        "height" => 32
    },
          "label" => nil,
    "description" => "<UITabBarSwappableImageVie....>"

在Android上，我可以使用它来列出类组件的所有值：

query("*", :class)

但是，我似乎无法在iOS上使用相同的命令。我得到了这个结果：

irb(main):135:0> query "*", :class
[
    [ 0] nil,
    [ 1] nil,
    [ 2] nil,
    [ 3] nil
]

我知道使用标签，我可以使用：accessibilityLabel来完成这项工作，但是当我尝试从类/ id / etc中获取值时却不能。

有人可以解释一下吗？

Answer 1

简短回答：'class'不是UIView实例上的选择器

答案很长：

# query( < look for some views >, < selector on the views found > )

# look for buttons marked 'big button' and call 'isSelected' selector on them
query("button marked:'big button'", :isSelected")

# look for labels marked 'title' and call 'text' selector on them
query("label marked:'title'", :text)

# look for all views and call 'class' selector on them
# whoops!  'class' is not a selector on UIView instances
query "*", :class

退后一步，我想我知道你要做什么 - 获得一个可见的全面视图列表。

查看https://github.com/jmoody/briar/blob/master/lib/briar/irbrc.rb

示例输出在此处：https://gist.github.com/jmoody/8031917

不是在查询中调用“class”，而是迭代查询返回的结果并查找“class”键的值。

query('*').map { |result| result['class'] }

Calabash iOS：如何使用query命令获取值

1 个答案: