我需要在我的捆绑中将regitration控制器覆盖1。
我在userbundle中创建了这个文件,但它给出了我在stackoverflow上看到很多但没有回复的错误。
错误是
ContextErrorException:运行时注意:TA \ UserBundle \ Controller \ RegistrationController :: registerAction()的声明应与E中的FOS \ UserBundle \ Controller \ RegistrationController :: registerAction(Symfony \ Component \ HttpFoundation \ Request $ request)兼容: \ php \ xampp \ htdocs \ platform \ src \ TA \ UserBundle \ Controller \ RegistrationController.php第9行
控制器
<?php
//src\TA\UserBundle\Controller\RegistrationController.php
namespace TA\UserBundle\Controller;
use Symfony\Component\HttpFoundation\RedirectResponse;
use FOS\UserBundle\Controller\RegistrationController as BaseController;
class RegistrationController extends BaseController
{
public function registerAction()
{
$form = $this->container->get('fos_user.registration.form');
$formHandler = $this->container->get('fos_user.registration.form.handler');
$confirmationEnabled = $this->container->getParameter('fos_user.registration.confirmation.enabled');
$process = $formHandler->process($confirmationEnabled);
if ($process) {
$user = $form->getData();
/*****************************************************
* Add new functionality (e.g. log the registration) *
*****************************************************/
$this->container->get('logger')->info(
sprintf('New user registration: %s', $user)
);
if ($confirmationEnabled) {
$this->container->get('session')->set('fos_user_send_confirmation_email/email', $user->getEmail());
$route = 'fos_user_registration_check_email';
} else {
$this->authenticateUser($user);
$route = 'fos_user_registration_confirmed';
}
$this->setFlash('fos_user_success', 'registration.flash.user_created');
$url = $this->container->get('router')->generate($route);
return new RedirectResponse($url);
}
return $this->container->get('templating')->renderResponse('FOSUserBundle:Registration:register.html.'.$this->getEngine(), array(
'form' => $form->createView(),
));
}
}
即使我改变了
public function registerAction()
到
public function registerAction(Request $request)
错误成了
ContextErrorException:运行时注意:TA \ UserBundle \ Controller \ RegistrationController :: registerAction()的声明应与E中的FOS \ UserBundle \ Controller \ RegistrationController :: registerAction(Symfony \ Component \ HttpFoundation \ Request $ request)兼容: \ php \ xampp \ htdocs \ platform \ src \ TA \ UserBundle \ Controller \ RegistrationController.php第9行
答案 0 :(得分:1)
这个对我有用。我的例子:
<?php
namespace FRMKS\FoodR\FoodApp\Controller;
use FOS\UserBundle\Controller\RegistrationController as BaseController;
use Symfony\Component\HttpFoundation\Request;
class RegistrationController extends BaseController
{
public function registerAction(Request $request)
{
$response = parent::registerAction($request);
// ... do custom stuff
return $response;
}
}
基本上你需要在'registerAction'函数中添加请求,参数'Request $ request',并将'request'参数传递给父'registerAction'函数
答案 1 :(得分:0)
您是否尝试将完整的'Symfony \ Component \ HttpFoundation \ Request $ request'放入方法定义中?
public function registerAction(Symfony\Component\HttpFoundation\Request $request) {}