Question

我正在创建对象并将其发布到webapi。基本上我只是无法获取序列化的东西，以便在json中包含$ type信息。以下是我试图编写的代码。之后是我期待的json。

       var cds = new List<CreditDefaultSwaps>()
        {
            new CreditDefaultSwaps() { ModelNumber = "SP8A1ETA", BrokerSpread = 0},
            new CreditDefaultSwaps() { ModelNumber = "SP3A0TU1", BrokerSpread = 0},
            new CreditDefaultSwaps() { ModelNumber = "SP4A102V", BrokerSpread = 0}
        };

        var client = new HttpClient {BaseAddress = new Uri("http://localhost/BloombergWebAPI/api/")};

        client.DefaultRequestHeaders.Accept.Clear();
        client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));

        // set up request object
        var oContract = new WebApiDataServiceRequest
        {
            RequestType = ReferenceDataRequestServiceTypes.ReferenceDataRequest,
            SwapType = BloombergWebAPIMarshal.SwapType.CDS,
            SecurityList = cds
        };

        Tried something like this and the var content was formatted as I would expect
        however I couldn't post the data using postasjsonasync

        //var content = JsonConvert.SerializeObject(oContract, Formatting.Indented,
        //    new JsonSerializerSettings { TypeNameHandling = TypeNameHandling.Objects });

           Console.ReadLine();

        var response = client.PostAsJsonAsync("bloombergapi/processbloombergrequest", oContract).Result;

以下是我想发布的json。我在上面的代码中遗漏了什么，我确信这是愚蠢的。

   {
      "$type": "BloombergWebAPIMarshal.WebApiDataServiceRequest, BloombergWebAPIMarshal",
      "RequestType": 3,
      "SwapType": 1,
      "SecurityList": [
        {
          "$type": "BloombergWebAPIMarshal.CreditDefaultSwaps, BloombergWebAPIMarshal",
          "ModelNumber": "SP8A1ETA",
          "BrokerSpread": 0
        },
        {
          "$type": "BloombergWebAPIMarshal.CreditDefaultSwaps, BloombergWebAPIMarshal",
          "ModelNumber": "SP3A0TU1",
          "BrokerSpread": 0
        },
        {
          "$type": "BloombergWebAPIMarshal.CreditDefaultSwaps, BloombergWebAPIMarshal",
          "ModelNumber": "SP4A102V",
          "BrokerSpread": 0
        }
      ]
    }

Answer 1

创建另一个重载使用此调用生成正确的请求：

var response = client.PostAsJsonAsync("processbloombergrequest", oContract, TypeNameHandling.Objects).Result

这是新的重载

public static Task<HttpResponseMessage> PostAsJsonAsync<T>(this HttpClient client, string requestUri, T value, TypeNameHandling typeNameHandling)
{

    return client.PostAsJsonAsync<T>(requestUri, value, CancellationToken.None, typeNameHandling);
}

public static Task<HttpResponseMessage> PostAsJsonAsync<T>(this HttpClient client, string requestUri, T value, CancellationToken cancellationToken, TypeNameHandling typeNameHandling)
{
    var formatter = new JsonMediaTypeFormatter
    {
        SerializerSettings = new JsonSerializerSettings()
        {
            TypeNameHandling = typeNameHandling
        }
    };

    return client.PostAsync<T>(requestUri, value, formatter, cancellationToken);
}

从Console创建Web API帖子以在json数据中包含$ type

1 个答案: