Question

使用此代码，我可以从mysql数据库获取数据并将其保存为.csv格式。

<?php
$filename = 'text.csv';
header('Content-type: application/csv');
header('Content-Disposition: attachment; filename='.$filename);

$host="";
$uname="";
$pass="";
$database = ""; 
$connection=mysql_connect($host,$uname,$pass); 
echo mysql_error();

//or die("Database Connection Failed");
$selectdb=mysql_select_db($database) or die("Database could not be selected");  
$result=mysql_select_db($database)
or die("database cannot be selected <br>");

$sqlagentdetails = "select * from users WHERE company_name != ''";
$rowresult = mysql_query($sqlagentdetails); 

echo "Coloumn 1";
echo "Column  2";
echo "\n";

while($row = mysql_fetch_array($rowresult, MYSQL_ASSOC))
{
    $myQuery =  mysql_query( /* query are goes to here...*/ );

    while($row = mysql_fetch_array($myQuery)){  

    $postcode = "{$row['postcode']}";  
    $paddress = "{$row['paddress']}";

    echo "$emailAgent  $paddress" . "\n";

    }
}
?>

它已成功将数据保存为.csv格式，但问题是当我查看.csv文件时。它显示的结果如下：

--------------------------
Column 1        Column 2
-------------------------
result 1 result 2
result 1 result 2
result 1 result 2
result 1 result 2

但TI应该显示为（IT必须显示每个列的每个值，而不是每个列的值）

--------------------------
Column 1        Column 2
-------------------------
result 1       result 2
result 1       result 2
result 1       result 2
result 1       result 2

如何将此.csv文件结果逐列保存？

Answer 1

如果您希望列之间有 TAB ，请将其放在echo语句中：

echo "Column 1\tColumn 2\n";

while($row = mysql_fetch_array($rowresult, MYSQL_ASSOC))
{
    $myQuery =  mysql_query( /* query are goes to here...*/ );

    while($row = mysql_fetch_array($myQuery)){  

        $postcode = $row['postcode'];  
        $paddress = $row['paddress'];

    echo "$postcode\t$paddress" . "\n";

}

当这是整个字符串时，也没有必要用"{...}"包装数组引用。

如何逐列输出csv数据

1 个答案: