我正在用Java编写FLV解析器并遇到了一个问题。该程序成功地将标记分析并分组到数据包中,并根据标题中的BodyLength标记为每个标记的主体正确识别和分配字节数组。但是在我的测试文件中,它成功完成了此操作,但在最后4个字节之前停止。
第一个文件中遗漏的字节序列是:
00 00 14 C3
在第二个:
00 00 01 46
显然这是两个文件的最后4个字节的问题但是我无法在逻辑中发现错误。我怀疑它可能是:
while (in.available() != 0)
但是我也怀疑是这种情况,因为程序成功进入最终标签的循环,但它只是停止4个字节短。任何帮助是极大的赞赏。 (我知道正确的异常处理尚未发生)
Parser.java
import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.lang.reflect.Array;
import java.net.URI;
import java.nio.ByteBuffer;
import java.nio.ByteOrder;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.InputMismatchException;
/**
*
* @author A
*
* Parser class for FLV files
*/
public class Parser {
private static final int HEAD_SIZE = 9;
private static final int TAG_HEAD_SIZE = 15;
private static final byte[] FLVHEAD = { 0x46, 0x4C, 0x56 };
private static final byte AUDIO = 0x08;
private static final byte VIDEO = 0x09;
private static final byte DATA = 0x12;
private static final int TYPE_INDEX = 4;
private File file;
private FileInputStream in;
private ArrayList<Packet> packets;
private byte[] header = new byte[HEAD_SIZE];
Parser() throws FileNotFoundException {
throw new FileNotFoundException();
}
Parser(URI uri) {
file = new File(uri);
init();
}
Parser(File file) {
this.file = file;
init();
}
private void init() {
packets = new ArrayList<Packet>();
}
public void parse() {
boolean test = false;
try {
test = parseHeader();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
if (test) {
System.out.println("Header Verified");
// Add header packet to beginning of list & then null packet
Packet p = new Packet(PTYPE.P_HEAD);
p.setSize(header.length);
p.setByteArr(header);
packets.add(p);
p = null;
try {
parseTags();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
} else {
try {
in.close();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
// throw FileNotFoundException because incorrect file
}
}
private boolean parseHeader() throws FileNotFoundException, IOException {
if (file == null)
throw new FileNotFoundException();
in = new FileInputStream(file);
in.read(header, 0, 9);
return Arrays.equals(FLVHEAD, Arrays.copyOf(header, FLVHEAD.length));
}
private void parseTags() throws IOException {
if (file == null)
throw new FileNotFoundException();
byte[] tagHeader = new byte[TAG_HEAD_SIZE];
Arrays.fill(tagHeader, (byte) 0x00);
byte[] body;
byte[] buf;
PTYPE pt;
int OFFSET = 0;
while (in.available() != 0) {
// Read first 5 - bytes, previous tag size + tag type
in.read(tagHeader, 0, 5);
if (tagHeader[TYPE_INDEX] == AUDIO) {
pt = PTYPE.P_AUD;
} else if (tagHeader[TYPE_INDEX] == VIDEO) {
pt = PTYPE.P_VID;
} else if (tagHeader[TYPE_INDEX] == DATA) {
pt = PTYPE.P_DAT;
} else {
// Header should've been dealt with - if previous data types not
// found then throw exception
System.out.println("Unexpected header format: ");
System.out.print(String.format("%02x\n", tagHeader[TYPE_INDEX]));
System.out.println("Last Tag");
packets.get(packets.size()-1).diag();
System.out.println("Number of tags found: " + packets.size());
throw new InputMismatchException();
}
OFFSET = TYPE_INDEX;
// Read body size - 3 bytes
in.read(tagHeader, OFFSET + 1, 3);
// Body size buffer array - padding for 1 0x00 bytes
buf = new byte[4];
Arrays.fill(buf, (byte) 0x00);
// Fill size bytes
buf[1] = tagHeader[++OFFSET];
buf[2] = tagHeader[++OFFSET];
buf[3] = tagHeader[++OFFSET];
// Calculate body size
int bSize = ByteBuffer.wrap(buf).order(ByteOrder.BIG_ENDIAN)
.getInt();
// Initialise Array
body = new byte[bSize];
// Timestamp
in.read(tagHeader, ++OFFSET, 3);
Arrays.fill(buf, (byte) 0x00);
// Fill size bytes
buf[1] = tagHeader[OFFSET++];
buf[2] = tagHeader[OFFSET++];
buf[3] = tagHeader[OFFSET++];
int milliseconds = ByteBuffer.wrap(buf).order(ByteOrder.BIG_ENDIAN)
.getInt();
// Read padding
in.read(tagHeader, OFFSET, 4);
// Read body
in.read(body, 0, bSize);
// Diagnostics
//printBytes(body);
Packet p = new Packet(pt);
p.setSize(tagHeader.length + body.length);
p.setByteArr(concat(tagHeader, body));
p.setMilli(milliseconds);
packets.add(p);
p = null;
// Zero out for next iteration
body = null;
Arrays.fill(buf, (byte)0x00);
Arrays.fill(tagHeader, (byte)0x00);
milliseconds = 0;
bSize = 0;
OFFSET = 0;
}
in.close();
}
private byte[] concat(byte[] tagHeader, byte[] body) {
int aLen = tagHeader.length;
int bLen = body.length;
byte[] C = (byte[]) Array.newInstance(tagHeader.getClass()
.getComponentType(), aLen + bLen);
System.arraycopy(tagHeader, 0, C, 0, aLen);
System.arraycopy(body, 0, C, aLen, bLen);
return C;
}
private void printBytes(byte[] b) {
System.out.println("\n--------------------");
for (int i = 0; i < b.length; i++) {
System.out.print(String.format("%02x ", b[i]));
if (((i % 8) == 0 ) && i != 0)
System.out.println();
}
}
}
Packet.java
public class Packet {
private PTYPE type = null;
byte[] buf;
int milliseconds;
Packet(PTYPE t) {
this.setType(t);
}
public void setSize(int s) {
buf = new byte[s];
}
public PTYPE getType() {
return type;
}
public void setType(PTYPE type) {
if (this.type == null)
this.type = type;
}
public void setByteArr(byte[] b) {
this.buf = b;
}
public void setMilli(int milliseconds) {
this.milliseconds = milliseconds;
}
public void diag(){
System.out.println("|-- Tag Type: " + type);
System.out.println("|-- Milliseconds: " + milliseconds);
System.out.println("|-- Size: " + buf.length);
System.out.println("|-- Bytes: ");
for(int i = 0; i < buf.length; i++){
System.out.print(String.format("%02x ", buf[i]));
if (((i % 8) == 0 ) && i != 0)
System.out.println();
}
System.out.println();
}
}
jFLV.java
import java.net.URISyntaxException;
public class jFLV {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Parser p = null;
try {
p = new Parser(jFLV.class.getResource("sample.flv").toURI());
} catch (URISyntaxException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
p.parse();
}
}
PTYPE.java
public enum PTYPE {
P_HEAD,P_VID,P_AUD,P_DAT
};
答案 0 :(得分:2)
您对available()
的使用和对read
的通话都被破坏了。不可否认,我会有点期望这对FileInputStream
没问题(直到你到达流的末尾,此时忽略read
的返回值仍然可能是灾难性的)但我个人认为流总是返回部分数据。
available()
只会告诉您现在是否有可用的数据。它非常很少有用 - 只需忽略它。如果要读取直到流的末尾,通常应该继续调用read
,直到它返回-1。诚然,把它与“我正在尝试阅读下一个街区”结合起来有点棘手。 (如果InputStream
有peek()
方法,那就太好了,但事实并非如此。您可以将其包装在BufferedInputStream
中并使用mark
/ reset
在每个循环的开始测试...丑陋,但它应该工作。)
接下来,你忽略了InputStream.read
的结果(在多个地方)。您总是使用此结果,而不是假设它已经读取了您要求的数据量。您可能需要一些辅助方法,例如
static byte[] readExactly(InputStream input, int size) throws IOException {
byte[] data = new byte[size];
readExactly(input, data);
return data;
}
static void readExactly(InputStream input, byte[] data) throws IOException {
int index = 0;
while (index < data.length) {
int bytesRead = input.read(data, index, data.length - index);
if (bytesRead < 0) {
throw new EOFException("Expected more data");
}
}
}
答案 1 :(得分:0)
您应该使用其中一种read方法而不是available,因为available()“返回可以从此输入流中读取(或跳过)的字节数的估计值,而不会在下次调用方法时阻塞对于此输入流。“
它不是为了检查您可以阅读的时间。